Alternative efficient ways to do partial fraction?

In summary, alternative ways to do partial fraction include the "cover-up method" and choosing "smart zeroes" of the denominator. These methods can help speed up the process, but may not always work fully. They involve factoring and setting up equations for the numerators to find the unknown coefficients.
  • #1
hanhao
20
0
what are alternative ways to do partial fraction?
other than the normal method of mulplying the whole term over and comparing coefficient which is super headache method

i heard of "cover-up method", gets the answer real quick

anyone have details to this?
 
Physics news on Phys.org
  • #2
By choosing "smart zeroes" of the denominator, you can speed up the process but this won't always work (fully).

For example, we wish to expand:

[tex]\frac{{x + 1}}
{{x^3 - 7x + 3}}[/tex]

So you start by factoring and introducing the unknown coëfficiënts:

[tex]\frac{{x + 1}}
{{x^3 - 7x + 3}} = \frac{{x + 1}}
{{\left( {x - 1} \right)\left( {x - 2} \right)\left( {x + 3} \right)}} = \frac{A}
{{x - 1}} + \frac{B}
{{x - 2}} + \frac{C}
{{x + 3}} = \frac{{A\left( {x - 2} \right)\left( {x + 3} \right) + B\left( {x - 1} \right)\left( {x + 3} \right) + C\left( {x - 1} \right)\left( {x - 2} \right)}}
{{\left( {x - 1} \right)\left( {x - 2} \right)\left( {x + 3} \right)}}[/tex]

Then you set up the equation for the numerators to be the same:

[tex]A\left( {x - 2} \right)\left( {x + 3} \right) + B\left( {x - 1} \right)\left( {x + 3} \right) + C\left( {x - 1} \right)\left( {x - 2} \right) = x + 1[/tex]

Traditionally, you would now expand the entire left side and then group in powers of x to get a system, which is still doable.

Another way to go on now would be to choose some values for x, preferably values which may simplify things, i.e. zeroes of the denominator:

[tex]\begin{gathered}
x = 1 \Rightarrow A\left( {1 - 2} \right)\left( {1 + 3} \right) = 2 \Leftrightarrow A = - \frac{1}
{2} \hfill \\
x = 2 \Rightarrow B\left( {2 - 1} \right)\left( {2 + 3} \right) = 3 \Leftrightarrow B = \frac{3}
{5} \hfill \\
x = - 3 \Rightarrow C\left( { - 3 - 1} \right)\left( { - 3 - 2} \right) = - 2 \Leftrightarrow C = - \frac{1}
{{10}} \hfill \\
\end{gathered} [/tex]

Which gives the result:

[tex]\frac{{x + 1}}
{{x^3 - 7x + 3}} = \frac{{ - 1}}
{{2\left( {x - 1} \right)}} + \frac{3}
{{5\left( {x - 2} \right)}} - \frac{1}
{{10\left( {x + 3} \right)}}[/tex]
 
  • #3


Thank you for your question. The "cover-up method" is a commonly used shortcut in partial fraction decomposition that can make the process quicker and easier. It involves covering up the variable in the denominator with a value that will make the fraction equal to zero, and then solving for the unknown coefficient. This method works well for simple fractions with linear denominators, but may not be as effective for more complex fractions. Another alternative method is the Heaviside cover-up method, which involves using a formula to determine the coefficients without having to solve for them individually. This method is useful for fractions with repeated linear factors. Additionally, there are computer programs and calculators that can perform partial fraction decomposition for more complex fractions. These methods can save time and reduce the chances of making errors, but it is important to understand the underlying concepts of partial fraction decomposition in order to use these shortcuts effectively.
 

1. How do you determine when partial fraction decomposition is necessary?

Partial fraction decomposition is necessary when you have a rational function with a denominator that can be factored into linear and irreducible quadratic factors. This method allows you to break down a complex fraction into simpler fractions, making it easier to integrate or solve.

2. What are the steps for performing partial fraction decomposition?

The steps for performing partial fraction decomposition are:

  1. Factor the denominator of the rational function into linear and irreducible quadratic factors.
  2. Write the partial fraction decomposition with unknown coefficients for each factor.
  3. Find the values of the unknown coefficients by equating the numerator of the original fraction to the sum of the numerators of the partial fractions.
  4. Write the final partial fraction decomposition with the determined coefficients.

3. Are there any restrictions for using partial fraction decomposition?

Yes, there are a few restrictions for using partial fraction decomposition. The rational function must have a proper fraction, meaning the degree of the numerator must be less than the degree of the denominator. Additionally, the denominator must be factorable into linear and irreducible quadratic factors.

4. Can partial fraction decomposition be used for improper fractions?

No, partial fraction decomposition can only be used for proper fractions. Improper fractions can be rewritten as a sum of a whole number and a proper fraction, where only the proper fraction can be decomposed using this method.

5. What are some real-world applications of partial fraction decomposition?

Partial fraction decomposition is used in many fields of science and engineering, such as signal processing, control theory, and chemical engineering. It is also used in physics and mathematics for solving integrals and differential equations. Additionally, partial fraction decomposition is used in economics and finance for financial modeling and analysis.

Similar threads

  • Calculus and Beyond Homework Help
Replies
8
Views
153
  • Introductory Physics Homework Help
Replies
8
Views
3K
Replies
11
Views
1K
Replies
2
Views
2K
  • Precalculus Mathematics Homework Help
Replies
14
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Precalculus Mathematics Homework Help
Replies
4
Views
2K
  • Precalculus Mathematics Homework Help
Replies
14
Views
2K
  • Precalculus Mathematics Homework Help
Replies
3
Views
2K
  • Precalculus Mathematics Homework Help
Replies
11
Views
2K
Back
Top