muon decay calculation


by ChrisVer
Tags: calculation, decay, muon
ChrisVer
ChrisVer is offline
#1
Dec17-13, 02:52 PM
P: 379
Please, I'd need some help. Although I am not sure if this is again the correct thread, but since it concerns muon decay I bring it here. So...

I am trying to find out why the differential below, in spherical cordinates becomes:
[itex]d^{3}p_{\bar{v_{e}}}=-\frac{E_{\bar{v_{e}}} E_{v_{μ}}}{E_{e}} dE_{\bar{v_{e}}} dE_{v_{μ}} dφ (0)[/itex]

I already have derived the equation:
[itex] E_{v_{μ}}^{2}= E_{\bar{v_{e}}}^{2}+E_{e}^{2}+2E_{\bar{v_{e}}}E_{e}cosθ (1)[/itex]
I also have the conservation of energy due to delta function:
[itex] E_{v_{μ}}= m_{μ}-E_{\bar{v_{e}}}-E_{e} (2)[/itex]

I stop in a very bad position not knowing how to continue:
[itex]d^{3}p_{\bar{v_{e}}}= p_{\bar{v_{e}}}^{2} dp_{\bar{v_{e}}} dcosθ dφ=E_{\bar{v_{e}}}^{2} dE_{\bar{v_{e}}} dcosθ dφ [/itex]
How would you recommend I continue? I would try to differentiate the [itex](1)[/itex] but it has also cosθ and generally a mess is happening. I also could try to differentiate [itex](2)[/itex] but I would get weird results not coinciding with [itex](0)[/itex]
Any suggestion?
(the mass of muon only exists, in the game, so the electron and neutrinos' masses are neglected, and thus their energies are equal to their momentum's magnitudes)
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Meir Achuz
Meir Achuz is offline
#2
Dec26-13, 07:53 AM
Sci Advisor
HW Helper
P: 1,937
Start with
[tex]d^3p_1d^3p_2d^3p_e\delta^4()/E_1E_2E_e[/tex].
[tex]\rightarrow d^3p_1d^3p_2\delta(E_1+E_2+E_e-M)/E_1E_2E_e[/tex],
[tex]\rightarrow 8\pi^2p_1dE_1p_2dE_2d\cos(\theta)\delta(E_1+E_2+E_e-M)/E_e[/tex],
with [itex]E_e=\sqrt{m^2+p^2_1+p^2_2+2p_1p_2\cos(\theta)}[/itex].
The delta function integration over d\theta gives
[tex]8\pi^2dE_1dE_2.[/tex]


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