|Jul16-12, 10:19 PM||#18|
Centre of gravity of a car
The load portion on the front axle when the car is leveled (Wf/W) is Lr/L [= 1 - Lf/L] (why?)
The load portion on the front axle when the rear axle is lifted (Wfu/W) is Lr'/(L cosA) [= (L cosA - Lf')/(L cosA) = 1 - Lf'/(L cosA)]
The load increase on the front axle (DWf) between the 2 states will be Wfu - Wf.
But: Lf' = Lf cosA - H sinA
Wfu/W = 1 - (Lf cosA - H sinA)/(L cosA)
Wfu/W = 1 - Lf/L + H/L tanA
Wfu/W = Wf/W + H/L tanA
Wfu/W - Wf/W = H/L tanA
(Wfu - Wf)/W = H/L tanA
DWf/W = H/L tanA
H = (L x DWf)/(W x tanA)
|Jul16-12, 11:47 PM||#19|
Thank you, thats exactly what i was looking for.
|Sep17-12, 03:16 PM||#20|
The link above helps tremendously http://www.team.net/TR8/tr8cca/wedge...ef/CG_def.html.
What if you now have passengers and the vehicle is on level ground? What would the height of the vehicles CG be? I do know the weight of the passengers along with their CG height.
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