
#1
Apr3013, 05:09 AM

P: 1,991

Consider a hollow cylinder carrying a current I and a wire outside the cylinder carrying a current I'.
Let's say the cylinder is symmetrical with even current distribution etc.. so the B field at any point (due to current in cylinder) within the cylinder is zero by Amperes Law. However, this doesn't mean the B field is zero within the cylinder entirely  there is a B field contribution from the wire. So my question is: What is the usefullness of Amperes Law? Does Ampere's Law only tell me something about the B field from a particular source? Also say we have a solid cylinder inside a hollow cylinder with radii a and b respectively. They have opposite current directions. Then by Ampere, the B field at some point P where a < P < b is given as ##B = \frac{\mu I}{2\pi r}, I ##the current in the solid cylinder. Is it really? The B field from the hollow cylinder will be in the opposite direction at P and so acts to cancel the B field at P from the solid cylinder thus resulting in zero net B field, no? Yet the B field at P is in fact nonzero? I understand how the non zero B field was obtained using Ampere's Law, but the Amperian loop which coincides with P does not simply shield the B field from the hollow cylinder. So I am struggling to see why the B field would be nonzero. Many thanks. 



#2
Apr3013, 06:11 AM

P: 58

well...i believe you should consider BiotSavart law to get into this..




#3
Apr3013, 06:18 AM

P: 1,991





#4
May113, 06:47 AM

P: 58

Importance of Ampere's Law
well, ampere law does explain it..but if you want to find the way it is done..you should use BiotSavart law to find out the magnetic field. take a infinitesimal element, find the conditions, integrate it..add the vectors..you wont find them to be zero.. although ampere's law deals with the magnetic field due to closed loop carrying a current. but still it is feasible..




#5
May113, 04:51 PM

P: 1,991

Actually given that the B field inside the hollow cylinder from the cylinder is zero, I don't really have a problem since the B field is exclusively from the solid cylinder inside.
However, now consider the following rearrangement: A solid cylinder enclosed in a hollow cylinder and a wire outside the hollow cylinder. Take some point ##a< P < b##. Then by Ampere's Law, the B field is ##\oint \underline{B} \cdot d\underline{s} = \mu_0 I_{enc} \Rightarrow B = \frac{\mu_o I_{enc}}{2\pi R}##. Now set up the wire such that the magnetic field it produces is in the opposite direction to the B field produced from the solid cylinder at P. (I.e so that the net B field is zero at B and the two B fields 'cancel'). We now know that the B field is zero (at P)but an application of Ampere's Law (as given before) gives a non zero field. Where is the flaw in this argument? The Amperian loop I choose to measure the B field from the cylinder does not 'shield' the B field from the wire and yet by Ampere's Law, provided we have a closed loop enclosing the current from the solid cylinder we attain a non zero B field. Thanks for any clarity, 



#6
May113, 06:10 PM

C. Spirit
Sci Advisor
Thanks
P: 4,938





#7
May213, 01:42 AM

P: 1,991

Hi WannabeNewton,
I see  so by including the wire this changes the magnetic field locally at point P (I.e it is no longer circular) and so ##\underline{B} \cdot d\underline{s} = B(2 \pi r)## no longer holds. So we have to consider the field due to all possible sources at point P before we consider what the dot product of B and ds looks like? 



#8
May213, 12:26 PM

C. Spirit
Sci Advisor
Thanks
P: 4,938

That is one way to do it yes. You can use superposition; see this tutorial: http://einstein1.byu.edu/~masong/ems...Q50/S3Q50.html



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