Determine Rate Law For Chem Reaction

[webdivx]

Can some body please help me on my homework. The problem is in the link image below (click to go to it)

http://img501.imageshack.us/img501/1126/helplr7.jpg"

I'd know how to do that problem if it said "initial rate (M/s)" in the last column, but it says "Reaction time (seconds)" and I don't know what to do in that situation.

My guess is that I would need to somehow use that "Reaction time in seconds" to convert it into the initial rate, but I have noo idea how to. If I can do that I know the problem is easy, but I don't know how to. Please help!

 

[Stevedye56]

Someone please correct me if I am wrong on this. I remember these as in you have to calculate the rate of change for X. When you calculate it the other concentrations can show no chage. Example: ----A---B---Rate M/s
1--1.0--2.0-----x
2--2.0--2.0-----x
3--1.0--1.0-----x

To calculate the rate for A you would use trials 1 and two because B is the same in this

Note: None of the values are negative, I just had problems if the hyphens were not in place, the table got messed up.

 

[Blueshift5]

Hello,

I am happy to assist you with your homework problem. To determine the rate law for a chemical reaction, we need to first understand the relationship between the rate of the reaction and the concentration of the reactants. This can be done by conducting several experiments and measuring the initial rate of the reaction at different concentrations of the reactants.

In this problem, the data is given in terms of reaction time (seconds) and concentration (M). To convert the reaction time into the initial rate, we can use the formula: initial rate = 1/reaction time. This will give us the initial rate in units of 1/s or s^-1.

Once we have the initial rates at different concentrations, we can plot a graph of initial rate vs. concentration and determine the order of the reaction with respect to each reactant. The overall rate law can then be determined by combining the orders of each reactant.

I hope this helps you solve the problem. If you have any further questions, please don't hesitate to ask. Good luck!