Weight displaced and volume displaced?

In summary, the conversation discusses the concept of neutral buoyancy and how it relates to a hot air balloon hovering in the air. It prompts the reader to consider Archimedes' principle and the buoyancy force, as well as the conditions for neutral buoyancy and the density of air. The conversation also suggests thinking about the weight and density of the balloon in order to determine the volume of displaced air.
  • #1
wrigglyworm
1
0

Homework Statement



you are hovering (no acceleration) in a hot air balloon of total weight (balloon+load+hot air) 18,000 N

a) what is the weight of displaced air?

b) what is the volume of displaced air?

Homework Equations



if i knew i wouldn't be asking

The Attempt at a Solution



i also do not know
 
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  • #2
Consider Archimedes' principle and the buoyancy force.
 
  • #3
What's are the conditions for neutral buoyancy? What's the (standard) density for air?
 
  • #4
Think about it this way. The baloon is hovering. It's not going up or down. Suppose it was slowly going down. Why would it be going down? Because every time it went down by 1mm, something heavy would be closer to the ground. That could be you in the baloon. But you're not going down. That means something equally heavy must have to go up when you go down. That's the displaced air. It must have the same weight as the thing that displaced it, because if it was lighter you'd go down, and if it was heavier you'd go up.

If you know what it weighs and you know its density, you can figure out it's volume. Do you know the density of air?
 
  • #5
the weight of the air that is displaced. However, I can explain the concept of weight displaced and volume displaced.

Weight displaced refers to the weight of the fluid (in this case, air) that is pushed aside or displaced by the object (hot air balloon). In other words, it is the weight of the air that would occupy the same space as the object if it were not there.

Volume displaced, on the other hand, refers to the volume of the fluid that is pushed aside or displaced by the object. In this case, it would be the volume of air that the hot air balloon takes up.

To find the weight of the displaced air, we can use the principle of buoyancy. This principle states that the weight of the fluid displaced by an object is equal to the weight of the object. Therefore, the weight of the displaced air would be equal to the weight of the hot air balloon, which is 18,000 N.

To find the volume of the displaced air, we can use the ideal gas law, which states that the volume of a gas is directly proportional to its temperature and inversely proportional to its pressure. Since the hot air balloon is hovering with no acceleration, we can assume that the temperature and pressure of the air inside and outside the balloon are the same. Therefore, the volume of the displaced air would be equal to the volume of the hot air balloon, which can be calculated using its dimensions.

In summary, the weight of the displaced air would be 18,000 N and the volume of the displaced air would depend on the dimensions of the hot air balloon.
 

1. How do you define weight displaced and volume displaced?

Weight displaced refers to the weight of fluid that is pushed aside when an object is placed in it. Volume displaced is the volume of fluid that is displaced or moved by an object placed in it.

2. What is the difference between weight displaced and volume displaced?

The main difference is that weight displaced is measured in units of weight, while volume displaced is measured in units of volume. Weight displaced also takes into account the density of the fluid, while volume displaced does not.

3. How is weight displaced and volume displaced related to buoyancy?

Weight displaced and volume displaced are both important factors in determining buoyancy. An object will float if the weight of the fluid it displaces is equal to or greater than its own weight. The volume of fluid displaced also affects the buoyancy force acting on an object.

4. How can you calculate weight displaced and volume displaced?

Weight displaced can be calculated by multiplying the volume of fluid displaced by the density of the fluid. Volume displaced can be calculated by dividing the weight of the object by the density of the fluid.

5. What are some real-life applications of weight displaced and volume displaced?

Weight displaced and volume displaced are important concepts in understanding the behavior of objects in fluids, such as ships floating on water or hot air balloons in the air. They are also used in calculating the weight and volume of objects, such as when determining the capacity of a container or the weight of a submerged object.

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