
#1
May1012, 11:00 PM

P: 354

but i need the derivative wrt time where theta depends on time




#2
May1012, 11:49 PM

Mentor
P: 20,988

$$\frac{d}{dt}sin^2(\theta) = \frac{d}{d\theta}sin^2(\theta)\cdot \frac{d\theta}{dt} = ? $$ 



#3
May1012, 11:58 PM

P: 354

then it is simply 2sin(theta)cos(theta)*(theta dot)




#4
May1112, 12:17 AM

Mentor
P: 20,988

whats the derivative of sin^2(theta)?
Yes, that's it.



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