- #1
r6mikey
- 11
- 0
[SOLVED] Another simple question that I don't get :(
Find the Length of the indicated curve
y=2x-3 x[1-3]
Arc Length=[tex]\int[/tex][tex]\sqrt{1+[f'(x)]^{2}dx}[/tex]
ok so y'=2 of course,
so it becomes a problem of [tex]\int from 1 to 3 for \sqrt{5}[/tex]
using substitution, u=5 ,and this is where i get a little confused...
du=0dx which would make dx=du/0
the answer becomes 2[tex]\sqrt{5}[/tex]
I'm sure I'm making it harder than it is, I always do... :(
Homework Statement
Find the Length of the indicated curve
y=2x-3 x[1-3]
Homework Equations
Arc Length=[tex]\int[/tex][tex]\sqrt{1+[f'(x)]^{2}dx}[/tex]
The Attempt at a Solution
ok so y'=2 of course,
so it becomes a problem of [tex]\int from 1 to 3 for \sqrt{5}[/tex]
using substitution, u=5 ,and this is where i get a little confused...
du=0dx which would make dx=du/0
the answer becomes 2[tex]\sqrt{5}[/tex]
I'm sure I'm making it harder than it is, I always do... :(