Can the path integral method explain the spreading of wave packets over time?

In summary: The Lagrangian formalism also makes it easier to incorporate symmetries and conservation laws into the equations of motion.
  • #1
kurious
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Why does a wave packet spread out in space as time passes?
What difference would it make to the universe if it did not?

And have a look at this link which shows a movie of "the time evolution of a quantum wave packet."
http://webphysics.davidson.edu/mjb/acs_transformations_qm/packet.html

Is the movie lacking any important information that I should know about a wave packet?
 
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  • #2
kurious said:
Is the movie lacking any important information that I should know about a wave packet?

That is a wave packet loses linear momentum as time progresses by spreading out and lowering the peak hence increasing its wavelength. The decrease in momentum is related to a decrease in kinetic energy of the wave. If it is a light wave, in contrast to matter wave traveling in vacuum, then the speed remains constant.
 
  • #3
kurious said:
Why does a wave packet spread out in space as time passes?
What difference would it make to the universe if it did not?

And have a look at this link which shows a movie of "the time evolution of a quantum wave packet."
http://webphysics.davidson.edu/mjb/acs_transformations_qm/packet.html

Is the movie lacking any important information that I should know about a wave packet?

I think of wave propagation in relation to its source. As the wave moves farther away from the source, it has to fill the volume vacated by the preceeding wave. Of course, this process changes if or when it incounters another system and is consummed.
 
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  • #4
Antonio Lao:
That is a wave packet loses linear momentum as time progresses by spreading out and lowering the peak hence increasing its wavelength. The decrease in momentum is related to a decrease in kinetic energy of the wave. If it is a light wave, in contrast to matter wave traveling in vacuum, then the speed remains constant.

Kurious:
Does kinetic energy become potential energy in the case of matter wave?
 
  • #5
kurious said:
Does kinetic energy become potential energy in the case of matter wave?

This is a very good question to which I don't have good answer at the moment but I can make a few educated guesses.

We know that all matter slow down when set in motion. This will include the planetary motion around the sun. Matter can slow down when it acquires and gains mass. Matter can slow down when it is challenge by opposing forces (frictions, field resistances, etc.).

But in QM, when the exact location of the electron is found, the wave packet collapses, i.e., the wave nature of the particle disappears and only the particle nature is left behind. But according to the Heisenberg's uncertainty principle, we can never find the exact location of the electron and the solidity of atom is just a balance of forces.

One can make the assumption that even energy has to have its relativeness. So for matter losing relative kinetic energy gaining back relative potential energy.

For all practical purposes, the photon is purely kinetic. Its rest mass is zero but its momentum is [itex] \frac{E}{c}[/itex].
 
  • #7
The conservation of energy is true only for an isolated thermodynamic system (mass and energy cannot enter or leave the system boundary). And it makes the following statement:

Total energy of the system is a constant and is equal to the sum of potential energy and kinetic energy.

For a closed thermodynmic system there is no mass crosses the system boundary. But its volume can vary. And also energy can enter or leave the system boundary.

The statement above is the simplest case of time independent Hamiltonian function. And the Hamiltonian approach was used in the beginning of quantum mechanics before Feynman replaced it with the Lagrangian formalism.
 
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  • #9
kurious said:
What is the advantage of the Lagrangian over the Hamiltonian in quantum mechanics?

It has to do with how each of the two formalisms deals with the concept of "path" in physics. Hamiltonian works good in classical mechanics but Lagrangian can work good both in classical and quantum mechanics.
 
  • #10
By the principle of continuity with its equation given by

[tex] \frac{\partial \rho}{\partial t} + \nabla \cdot \left(\rho \vec{v}\right) =0 [/tex]

the concept of density is implied to exist but not equal to zero. So the path of flow can be analyzed.

But in quantum mechnanics (discrete systems), the path of a quantum particle such as an electron has no meaning since each point in the path is associated with an uncertainty of position and velocity. There is no way to know whether the electron has actually move from here to there or there to here. No way of knowing whether the motion is forward or backward in time. The Hamiltonian is soluble if it is time independent but if time need to be analyzed then a direction of its flow must be accounted by the analysis. But in Lagrangian, since it is the difference between potential and kinetic energy, the description of the direction is not necessary, but the result is a principle of least action which is a more elegant form of Fermat's principle of least time.
 
  • #11
Since the Lagrangian is really a continuum formalism, Feynman came up with path integral method for sum over histories of all possible paths and each of these paths is associated with a probability function. The most probable path is the classical path.
 

1. What is a wave packet?

A wave packet is a localized disturbance or oscillation that travels through space and time, carrying energy and momentum. It can be thought of as a group of waves with a specific amplitude, frequency, and phase.

2. How do wave packets spread out?

Wave packets spread out due to the phenomenon of diffraction, which is the bending and spreading of waves as they pass through an opening or around an obstacle. This is caused by the interference of different parts of the wave packet with each other.

3. What factors affect the spreading of wave packets?

The spreading of wave packets is influenced by several factors, including the initial size and shape of the packet, the wavelength and frequency of the waves, and the medium through which the waves are propagating. The amount of spreading also depends on the distance traveled by the wave packet.

4. Why is the spreading of wave packets important?

The spreading of wave packets is important in many areas of science, including optics, acoustics, and quantum mechanics. It allows us to understand and predict the behavior of waves in different contexts, and it has practical applications in technologies such as radar, sonar, and medical imaging.

5. Is there a limit to how much a wave packet can spread out?

Yes, there is a limit to how much a wave packet can spread out. This limit is determined by the Heisenberg uncertainty principle in quantum mechanics, which states that it is impossible to know both the position and momentum of a particle (or wave packet) with absolute certainty. Therefore, the more precisely we know the position of a wave packet, the less precisely we know its momentum, and vice versa.

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