Indirect vs. Direct Bandgap Semiconductors

In summary, dielectrics have an upcoming exam and are looking for help. Semiconductors have a direct bandgap and indirect bandgap, which is determined by the crystal structure. The difference in behavior comes from the different crystal structures, and the tight binding model is one way that the behavior is determined. There is no easy answer to why the difference exists.
  • #1
question2004
8
0
I have one question to trouble you.

Why some semiconductors have a direct bandgap, while some have an indirect bandgap? Is there any very crude "thumb rule" of predicting/justifying it? Thanks a lot
 
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  • #2
bandgap= ?
are you talking about ttl vs mos?
 
  • #3
Bandgap in semiconductor is the energy gap between the conduction and valence band. Whether a semiconductor's bandgap is direct or indirect can be determined from the E-k diagram, which is obtained by solving Bloch equation using comprehensive numerical technique. I don't think there's a rule of thumb that allow us to specify the bandgap characteristic from cold. But to date most of the technologically exploited III-V semiconductor compound are direct bandgap (GaAs, InP etc), while group IV are indirect (eg Si, Ge).
 
  • #4
Why the big difference?

hi!

A question...why the big difference? Let's say Si and Ge where both have the same structure, the only difference is the 18 extra electrones, but Si have an indirect bandgap and Ge a direct. What in the theory makes the band structure direct or indirect bandgap? Is it that the Bolch waves of the valence electrones "see" different amount of electrons and therefore feel a different potensial or the small difference in cell parameter or something completely different?

Dielectra (...exame soon :uhh: )
 
  • #5
Dielectra said:
hi!

A question...why the big difference? Let's say Si and Ge where both have the same structure, the only difference is the 18 extra electrones, but Si have an indirect bandgap and Ge a direct. What in the theory makes the band structure direct or indirect bandgap? Is it that the Bolch waves of the valence electrones "see" different amount of electrons and therefore feel a different potensial or the small difference in cell parameter or something completely different?

Dielectra (...exame soon :uhh: )

There isn't anything obvious, or "rule of thumb" to know which will give you wish. The only way that I know is via direct band structure calculation and/or experimental observation. There is nothing obvious simply by looking at either the atomic structure, or the crystal structure. The crystal structure especially can severely influence the band structure, but again, there is nothing direct that I know of that can point one way or the other.

Zz.
 
  • #6
I suspect that the big difference between the behaviors of Si and Ge comes from the differing crystal structures (in addition to other possibilities). Si has a diamond structure, while Ge has a cubic close packed structure...that by itself provides more than a plausibility argument for the different dispersions.
 
  • #7
ok...

I read some more...and do you think it can be a result of the tight binding model? And then because of overlap of atomic orbitals? Then for Si we get s(+)-p(+)-p(-)-s(-) because of a high Vss potensial and a smaller Vxx, and the valence electrons and for Ge is s(+)-p(+)-s(-)-p(-). Can we then get an easier exitation of electrons from p(+) to s(-) in Ge than p(+) to S(-) in Si? Can that be the case?
 
  • #8
Dielectra said:
ok...

I read some more...and do you think it can be a result of the tight binding model? And then because of overlap of atomic orbitals?

Unfortunately, your question now doesn't make a lot of sense. It is BECAUSE of the overlap of atomic orbitals that you have to consider the tight-binding model. They are not different things.

Then for Si we get s(+)-p(+)-p(-)-s(-) because of a high Vss potensial and a smaller Vxx, and the valence electrons and for Ge is s(+)-p(+)-s(-)-p(-). Can we then get an easier exitation of electrons from p(+) to s(-) in Ge than p(+) to S(-) in Si? Can that be the case?

It isn't this easy. Tight-binding model can include nearest neighbor, next nearest neighbor, next next nearest neighbor, etc. It depends on how much there is an overlap, and the crystal structure. That is why you have the so called hopping integral.

Zz.
 
  • #9
Direct semiconductors have minimum conduction band and maximum valence band at k=0 in E-k diagram. That’s allows direct carrier recombination.
In indirect semiconductors (Si) electron got some energy in minimum conduction band and mediator needed for transferring energy (phonons usually) in recombination process.
So it’s big difference in carrier lifetime.
If you asked HOW it happens – the answer is – such E-k diagram.
If you asked WHY it happens – nobody knows I guess… ))))
 

1. What is the difference between indirect and direct bandgap semiconductors?

Indirect bandgap semiconductors have a smaller energy difference between their valence band and conduction band, making it more difficult for electrons to transition between them. Direct bandgap semiconductors have a larger energy difference, allowing for more efficient electron transitions.

2. Which type of bandgap is preferred for optoelectronic devices?

Direct bandgap semiconductors are preferred for optoelectronic devices because they have a higher probability of emission or absorption of light. This is due to the larger energy difference between the valence and conduction bands.

3. How does the bandgap affect the conductivity of a semiconductor?

The bandgap determines the minimum energy required for an electron to move from the valence band to the conduction band. In indirect bandgap semiconductors, this energy difference is smaller, making it more difficult for electrons to transition and therefore reducing the conductivity. In direct bandgap semiconductors, the larger energy difference allows for more efficient electron transitions and higher conductivity.

4. Can indirect bandgap semiconductors be used in optoelectronic devices?

Yes, they can be used, but they are less efficient compared to direct bandgap semiconductors. Indirect bandgap semiconductors require additional processes to facilitate light emission or absorption, which can decrease the overall efficiency of the device.

5. What is the impact of temperature on the bandgap of a semiconductor?

As the temperature increases, the bandgap of a semiconductor decreases. This is because at higher temperatures, more electrons are excited from the valence band to the conduction band, reducing the effective bandgap energy. This can affect the performance of optoelectronic devices as their efficiency may decrease at higher operating temperatures.

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