- #1
Pythagorean
Gold Member
- 4,401
- 313
[tex] \frac{e^{2x}}{e^{2x}+{3e^x}+2} [/tex]
I tried factoring the bottom to ([tex]{e^x+2}[/tex])([tex]{e^x+1}[/tex]) and using PFDs
and I've also tried [tex] u=2x [/tex] and [tex] u=e^x [/tex]
We haven't covered e operations in class and th book gives no examples. I assumed it would just be simple enough to do (A + B)e^x.
The book's answer is [tex] ln \frac{({e^x}+2)^2}{e^x+1} [/tex]
I've filled up six pages with this problem, and I'm so close. is there something I'm forgetting from back in the day?
I tried factoring the bottom to ([tex]{e^x+2}[/tex])([tex]{e^x+1}[/tex]) and using PFDs
and I've also tried [tex] u=2x [/tex] and [tex] u=e^x [/tex]
We haven't covered e operations in class and th book gives no examples. I assumed it would just be simple enough to do (A + B)e^x.
The book's answer is [tex] ln \frac{({e^x}+2)^2}{e^x+1} [/tex]
I've filled up six pages with this problem, and I'm so close. is there something I'm forgetting from back in the day?
Last edited: