- #1
vabamyyr
- 66
- 0
I have a question:
what is lim (n--->infinity)= 1/(3+(-1)^n))? My opinion that this limit does not exist.
what is lim (n--->infinity)= 1/(3+(-1)^n))? My opinion that this limit does not exist.
vabamyyr said:I have a question:
what is lim (n--->infinity)= 1/(3+(-1)^n))? My opinion that this limit does not exist.
manoochehr said:for example: (-1)^1/2 does not exist.
The equation for the limit of 1/(3+(-1)^n) is lim(n->∞) 1/(3+(-1)^n).
Yes, the limit of 1/(3+(-1)^n) does exist. It approaches two different values depending on whether n is an even or odd number.
The limit of 1/(3+(-1)^n) as n approaches infinity is 1/3. This is because as n gets larger, the term (-1)^n becomes insignificant and the limit approaches 1/3.
Yes, there are multiple methods for finding the limit of 1/(3+(-1)^n). One method is to use the limit laws and simplify the equation to determine the limit. Another method is to use the Squeeze Theorem to show that the limit is equal to a known value.
The value of n affects the limit of 1/(3+(-1)^n) by determining which value the limit approaches. If n is an even number, the limit approaches 1. If n is an odd number, the limit approaches 0.