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Derivatives of partial fractions 
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#1
Oct1410, 09:59 PM

P: 15

I'm having issue with one problem. We're asked to break down the problem into partial fractions to solve for the integral.
Well, I'm stuck on one. I'm being asked for the values of A, B, and C for the following problem. ∫((9x^2+13x83)/((x3)(x^2 + 16)))dx I can get it worked down pretty far, but I'm continually given back that I've done it incorrectly. Broken down: (9x^2+13x83)/((x3)(x^2 + 16)) = A/(x3) + (bx + c)/(x^2 + 16) From there, I get (multiplying both sides by the common denominator, and now only working with the right side as it's the only one that needs to be worked): A(x^2+12) + Bx(x3) + C(x3) = ax^2 + 12A + Bx^2  3Bx + Cx  3C = (A+B)x^2 + (C3B)x + (12A  3C) Therefor: 9x^2 + 13x 83 = (A+B)x^2 + (C3B)x + (12A  3C) Breaking it down further, I get: A + B = 9 3B  C = 13 12A  3C = 83 I'm thinking something may be wrong with my values in the second part. Any help would be appreciated. Whatever answers I put in, I'm marked as incorrect. I went so far as to plug the last little part I posted into WolframAlpha to confirm, and it spits the same answers I've been getting. I get the feeling that I did something incorrectly earlier on. 


#2
Oct1510, 06:37 AM

P: 297




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