- #1
rocapp
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Homework Statement
See attached image
Homework Equations
Δphi = 2pi(Δx/λ) + Δphi0 = 2pi(m) -- at the maximum
Δphi = (m + .5) (2pi) -- at the minimum
The Attempt at a Solution
The first step should be to solve for lambda, the wavelength.
So I plug in the knowns:
At 30 cm the amplitude is a maximum, so:
Δphi = 2pi(Δx/λ) + Δphi0 = 2pi(m)
Δphi = 2pi(30/λ) + Δphi0 = 2pi(m)
I am not sure what to do next. I tried too many times, so it now displays the answer as λ = 80 cm, but I'm not sure why that is true. I need help on the rest.
I'm just not sure what to do since I am missing more than one variable.