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Soaring Crane
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Homework Statement
Exactly how do you find the theoretical yield of methyl m-nitrobenzoate from 10.0 g of benzoic acid?
Homework Equations
1) Ph-COOH + CH3OH + H2SO4 --> Ph-COOCH3
2) Ph-COOCH3 + HNO3 + H2SO4 --> methyl m-nitrobenzoate
The Attempt at a Solution
10.0 g benzoic acid*(1 mol benzoic acid/122.122 g benzoic acid)*(1 mol methyl benzoate/1 mol benzoic acid)*(136.149 g methyl benzoate/1 mol methyl benzoate) = 11.15 g methyl benzoate from FIRST STEP as theoretical yield
11.15 g methyl benzoate*(1 mol methyl benzoate/136.149 g methyl benzoate)*(1 mol methyl m-nitrobenzoate/1 mol methyl benzoate)*(181.147 g methyl m-nitrobenzoate/1 mol methyl m nitrobenzoate) = 14.83 g methyl m-nitrobenzoate from 10.0 g benzoic acid as theoretical yield?
Thanks.
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