- #1
rdn98
- 39
- 0
The length of a metal rod is measured to be 20.08 cm using a steel ruler when both the rod and the ruler are at 22oC. Both the rod and the ruler are raised to a temperature of 253oC. When the rod is measured at this higher temperature, its length is found to be 20.32 cm.
****
a) What is the coefficient of expansion of the metal?
b) You now make a rod of the same material but with twice the length. What will it coefficient of expansion be?
c) You now make a rod of the same material but with twice the diameter. What will it coefficient of expansion be?
//////
So far I am stuck on part a. If I can get this part, then I should be able to get the rest.
Now I know that the equation is delta L=L*(coefficient of expansion)*(delta T)
Now it appears that I have all the informatin given in the problem, so I plug it into the equation, but it doesn't work. Then I realize that the ruler is stretching also, which means the number scale on the ruler also changes. Now I have to somehow relate that number scale to the coefficient of expansion, but I'm not sure how.
I know from the book at the coefficient of expansion for steel is 11*10^-6 /degree C.
****
a) What is the coefficient of expansion of the metal?
b) You now make a rod of the same material but with twice the length. What will it coefficient of expansion be?
c) You now make a rod of the same material but with twice the diameter. What will it coefficient of expansion be?
//////
So far I am stuck on part a. If I can get this part, then I should be able to get the rest.
Now I know that the equation is delta L=L*(coefficient of expansion)*(delta T)
Now it appears that I have all the informatin given in the problem, so I plug it into the equation, but it doesn't work. Then I realize that the ruler is stretching also, which means the number scale on the ruler also changes. Now I have to somehow relate that number scale to the coefficient of expansion, but I'm not sure how.
I know from the book at the coefficient of expansion for steel is 11*10^-6 /degree C.