How Do You Model a Mass-Spring-Damper System for a Rotating Body?

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In summary, the conversation discusses a mass-spring-damper system consisting of a rotating body, a flat spring, a damper, and a connecting rod. The goal is to find the differential equation for the oscillation/vibration of the rotating body. Two possible solutions are presented, but without a picture of the setup, it is not possible to determine which equation is correct.
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Homework Statement



http://img515.imageshack.us/img515/2668/ohyxf6.jpg
The mass-spring-damper-system is consist of a rotating body (Jo), a flat spring (E, I), a damper (b) and a connecting rod. Only the mass of the rotating body is to be considered. It is assumed that there's only a small angular travels due to the oscillation/vibration.

Find the differential equation φ(t) for the oscillation/vibration of the rotating body.

Values given: Jo = 0.3 kg/m² ; b = 200 kg/s ; a = 25cm ; L = 20 cm

Homework Equations


[tex]F_{D} = [/tex] [tex]b . a . \dot{\varphi}[/tex]

[tex]F_{F} = [/tex] [tex]c .a . \varphi[/tex]

The Attempt at a Solution



i have came up with two approaches.. but i don't know which one is correct

Solution 1:

[tex]J_{o}\ddot{\varphi} = -F_{F} . a - F_{D} . a[/tex]

[tex]J_{o}\ddot{\varphi} + b . a^{2} . \dot{\varphi} + c . a^{2} . \varphi = 0[/tex]

[tex]\ddot{\varphi} + \frac{b . a^{2}}{J_{o}} . \dot{\varphi} + \frac{c . a^{2}}{J_{o}} . \varphi = 0[/tex]

[tex]with[/tex]
[tex] 2\delta = \frac{b . a^{2}}{J_{o}} ; \omega{o}^{2} = \frac{c . a^{2}}{J_{o}}[/tex]

Solution 2:

[tex]m . a . \ddot{\varphi} = -F_{F} - F_{D} [/tex]

[tex]m . a . \ddot{\varphi} + b . a \dot{\varphi} + c . a . \varphi = 0 [/tex]

[tex]\ddot {\varphi} + \frac{ba}{ma} \dot{\varphi} + \frac {ca}{ma}\varphi = 0[/tex]

[tex]with[/tex]
[tex] 2\delta = \frac{b}{m} ; \omega_{o}^{2} = \frac {c}{m} [/tex]

both would give different answers for calculating other unknowns.. so i wonder which one is correct ?
 
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  • #2
It is not possible to decide without a heavy dose of guesswork which of the two equations is correct without a picture of the setup. Alas, the link to the figure is broken. :confused:
 
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1. What is a mass-spring-damper system?

A mass-spring-damper system is a mechanical system that consists of a mass, a spring, and a damper. It is used to model the behavior of many real-world systems, such as a car's suspension or a door's hinge.

2. How does a mass-spring-damper system work?

In a mass-spring-damper system, the mass is connected to a spring and a damper. The spring provides a restoring force that is proportional to the displacement of the mass, while the damper provides a damping force that is proportional to the velocity of the mass. Together, these forces allow the system to oscillate around an equilibrium position.

3. What factors affect the behavior of a mass-spring-damper system?

The behavior of a mass-spring-damper system is affected by several factors, including the mass of the object, the stiffness of the spring, and the damping coefficient of the damper. These parameters can be adjusted to control the frequency, amplitude, and damping of the system's oscillations.

4. How is a mass-spring-damper system represented mathematically?

A mass-spring-damper system can be represented using a second-order differential equation, known as the equation of motion. This equation describes the relationship between the forces acting on the mass and the resulting displacement over time. It can be solved using mathematical techniques, such as Laplace transforms, to predict the behavior of the system.

5. What are the applications of a mass-spring-damper system?

Mass-spring-damper systems have a wide range of applications in engineering and physics. They are commonly used in the design of mechanical systems, such as shock absorbers, vibration isolators, and suspension systems. They are also used in the study of oscillatory motion and in the development of control systems for various industrial processes.

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