How high does the ball rise?

  • Thread starter Leo34005
  • Start date
  • Tags
    Ball Rise
In summary, the question relates to a tennis ball being shot vertically upwards in an evacuated chamber without air resistance. The initial speed is given as 20m/s at time t=0s. The question asks for the height the ball rises and the approximate time it takes to reach its maximum height. The relevant equations involve initial speed, gravity, and time. By dividing the initial speed by gravity, the time to reach the top can be calculated. To find the height, the time is multiplied by the initial velocity and divided by 2, or the formula ymax = Velocityinitial*Time - 1/2Acceleration*Time2 can be used.
  • #1
Leo34005
51
0

Homework Statement



A tennis ball is shot vertically upward in an evacuated chamber(neglect air resistance) with an initial speed of 20m/s at time t=0s.

How high does the ball rise?

A)98.0m
B)72.4m
C)20.4m
D)10.2m
E)40.8m


Approximately how long does it take the tennis ball to reach its maximum height?

A)4.08s
B)9.08s
C)0.50s
D)6.08s
E)2.04s

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
  • #2
What are your thoughts and your equations regarding this matter?
 
  • #3
Its a freefall question regarding physics
 
  • #4
And what do you know about free fall questions regarding physics? What are the relevant equations?
 
  • #5
Dont know anything. Would you mind?
 
  • #7
Leo34005 said:

Homework Statement



A tennis ball is shot vertically upward in an evacuated chamber(neglect air resistance) with an initial speed of 20m/s at time t=0s.

How high does the ball rise?

A)98.0m
B)72.4m
C)20.4m
D)10.2m
E)40.8m


Approximately how long does it take the tennis ball to reach its maximum height?

A)4.08s
B)9.08s
C)0.50s
D)6.08s
E)2.04s

Homework Equations





The Attempt at a Solution





I learn the reasoning behind the equations, this let's you forget the equations formal setup while still being able to work it out

initial speed/gravity = time it takes to reach the top
so in this particular one it would be

20 divided by 9.8 (constant acceleration caused by gravity)

That gives you your time

Take the time that you got and times it by the initial velocity and divide it by 2

(2.04 * 20) / 2

now this is a home-brew formula that i use to save some time when I don't need to be exact, itll be 0.1 off or somewhere around that area so if you need it to be exact then you need to do

(20*2.04)-(4.9*2.042)

20 is the initial velocity as he throws it up

2.04 is the time it takes for it to reach the top

4.9 is half of 9.8, which is the acceleration caused by gravity

the formula is

ymax = Velocityinitial*Time - 1/2Acceleration*Time2

Hope this amatuer helped out a bit.

Rise = C
Time = E
 

1. How is the height of a ball's rise measured?

The height of a ball's rise is typically measured from the point of release to the highest point the ball reaches before falling back down.

2. What factors affect the height of a ball's rise?

The height of a ball's rise is affected by several factors, including the initial velocity of the ball, the force applied to the ball, air resistance, and gravity.

3. Is there a maximum height that a ball can reach?

Yes, there is a maximum height that a ball can reach. This is determined by the initial velocity of the ball and the force applied to it, as well as external factors such as air resistance and gravity.

4. Can the height of a ball's rise be calculated?

Yes, the height of a ball's rise can be calculated using the equations of motion, which take into account the initial velocity, force, and other factors mentioned above.

5. How does the height of a ball's rise change over time?

The height of a ball's rise changes over time as the ball is affected by gravity and air resistance. It reaches its maximum height at a certain point and then begins to fall back down to the ground.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
674
  • Introductory Physics Homework Help
Replies
2
Views
1K
Replies
5
Views
3K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
8
Views
5K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
1
Views
3K
Back
Top