Extrema in Several Variables: A different way?

In summary, the "first derivative test" is a simpler test than the "second derivative test" that can be used to find max/mins in a single variable.
  • #1
nth.gol
2
0
Hi,

In high school, I was shown an unconventional but quicker way to find max/mins. I'm not sure how common it is but we did it because we learned to curve sketch without calculus first.

Take f'(x) =0, and solve for the roots. Construct a number line and place all roots on the number line. Alternate + - from the right, unless there is a negative out front, and don't change signs around squared roots.

From here you extrapolate max mins based on sign. This is all nice and dandy compared to the first derivative test.

In several variables, however, I am currently being taught to use the partial second derivative or Determinant test.
Is there a better way? A quicker one like this? I understand geometrically the implications of the second partial test, and the cases where the pure and mixed partials affect the type of extrema. But is there a similar test to that in single variable?

Thank you
 
Physics news on Phys.org
  • #2
That is, in fact, what is known as the "first derivative test". It is typically given in most Calculus texts just before the "second derivative test". It is simpler than the second derivative test in that you do not need to find the second derivative. However, it also requires that you be able to find the sign of that first derivative on intervals rather than at individual points as with the second derivative test. Which is easier really depends upon the function.
 
  • #3
HallsofIvy said:
That is, in fact, what is known as the "first derivative test". It is typically given in most Calculus texts just before the "second derivative test". It is simpler than the second derivative test in that you do not need to find the second derivative. However, it also requires that you be able to find the sign of that first derivative on intervals rather than at individual points as with the second derivative test. Which is easier really depends upon the function.

Im not sure you really answered my question, but thanks for the input.
Is there another test in several variables?
 

1. What is the concept of extrema in several variables?

The concept of extrema in several variables is a way of finding the maximum and minimum values of a function that depends on multiple variables. It involves finding critical points and using the second derivative test to determine whether they are local maxima, local minima, or saddle points.

2. What is the difference between local and global extrema?

Local extrema refer to the maximum or minimum values of a function within a specific region or neighborhood. Global extrema, on the other hand, refer to the maximum or minimum values of a function over its entire domain.

3. How is the second derivative test used to find extrema in several variables?

The second derivative test involves calculating the determinant of the Hessian matrix at a critical point. If the determinant is positive, the critical point is a local minimum. If the determinant is negative, the critical point is a local maximum. If the determinant is zero, further analysis is needed to determine the nature of the critical point.

4. Can a function have more than one critical point?

Yes, a function can have multiple critical points. In fact, a function can have critical points at every point where its partial derivatives are equal to zero. This is why the second derivative test is important in determining the nature of each critical point.

5. How are extrema in several variables applied in real-life situations?

Extrema in several variables are commonly used in optimization problems, such as finding the maximum or minimum value of a production process. They are also used in economics, physics, and other fields to analyze and optimize complex systems with multiple variables.

Similar threads

  • Calculus and Beyond Homework Help
Replies
11
Views
2K
  • Calculus and Beyond Homework Help
Replies
7
Views
4K
  • Calculus and Beyond Homework Help
Replies
5
Views
2K
  • Calculus
Replies
1
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
Replies
3
Views
1K
  • Special and General Relativity
Replies
11
Views
164
  • Calculus and Beyond Homework Help
Replies
1
Views
2K
Replies
8
Views
10K
  • Calculus
Replies
5
Views
3K
Back
Top