Force constant of rear suspension of car

[Huskies213]

Can anyone help with the formula set ups for this ?

A 110 kg box is loaded into the trunk of a car. If the height of the car's bumper decreases by 13 cm, what is the force constant of the rear suspension ?

 

[d_leet]

Can anyone help with the formula set ups for this ?

A 110 kg box is loaded into the trunk of a car. If the height of the car's bumper decreases by 13 cm, what is the force constant of the rear suspension ?

Sounds like a Hooke's law problem, F = kx, k is the spring (force?) constant, and x is the displacement from the equilibrium position, how much the spring is compressed or stretched. Does this help?

 

[quicknote]

The force constant of the rear suspension of a car can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. In this case, the displacement is the 13 cm decrease in the height of the car's bumper and the force is the weight of the 110 kg box.

The formula for Hooke's Law is F = -kx, where F is the force, k is the force constant, and x is the displacement. Rearranging the formula to solve for k, we get k = -F/x.

Plugging in the values, we get k = -(110 kg * 9.8 m/s^2) / (0.13 m) = -847.69 N/m.

Therefore, the force constant of the rear suspension of the car is approximately 847.69 N/m. This means that for every 1 meter the suspension is compressed, it will exert a force of 847.69 N. This information can be useful for designing and adjusting the suspension system of a car for optimal performance and comfort.

 

[kyle8921]

The force constant of the rear suspension of a car is a measure of how stiff or rigid the suspension is. It is typically represented by the symbol "k" and is measured in units of force per unit length, such as N/m or lb/in. The formula for calculating the force constant is as follows:

k = F / x

Where k is the force constant, F is the applied force, and x is the displacement.

In this scenario, we can use the weight of the box (110 kg) as the applied force, and the decrease in height of the bumper (13 cm = 0.13 m) as the displacement. Therefore, the force constant would be:

k = (110 kg) / (0.13 m) = 846.15 N/m

This means that for every unit of length the bumper decreases, there is a force of 846.15 N acting on the suspension. This information can be useful in understanding the performance and handling of the car, as well as determining any necessary adjustments to the suspension.