Pendulum Motion (Simple Harmonic Motion)

In summary, we have a 180 g mass on a 2.5m long string being pulled 6.6 degrees to one side and released. To find the time it takes for the pendulum to reach 2.7 degrees on the opposite side, we first find the time it takes for the pendulum to swing 6.6 degrees (0.12 rad) using the equation theta(t) = A * cos(omega * t + phi) and the given values for A and omega. This results in a time of 0.59 seconds. Then, using the same equation, we can find the time it takes for the pendulum to swing the remaining 2.7 degrees (0.047 rad),
  • #1
Gotejjeken
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Homework Statement


A 180 g mass on a 2.5m long string is pulled 6.6 degrees to one side and released. How long does it take for the pendulum to reach 2.7 degrees on the opposite side?

Homework Equations



omega = sqrt(g/L)
theta = S/L
theta(t) = A * cos(omega * t + phi)

The Attempt at a Solution



I am looking at this problem in two parts, one is the time it takes the pendulum to swing 6.6 degrees (0.12 rad) and the other is how long it takes for the pendulum to go the remaining 2.7 degrees (0.047 rad). I have:

omega = sqrt(g/L) = 1.98 rad/s

For time it takes to swing 0.12 rad:

theta = S/L => s = L * theta => s = 0.3m = A

theta(t) = A * cos(omega * t + phi) => 0.12rad = 0.3 * cos(1.98t) => t = 0.59s

For time it takes to swing 0.047 rad:

theta = S/L => s = L * theta => s = 0.118m = A

theta(t) = A * cos(omega * t + phi) => 0.047rad = 0.118 * cos(1.98t) => t = 0.59s

Now, I know for a fact the second part is wrong as the pendulum doesn't go nearly as far. For the first part I left the phase constant as 0 since the pendulum is being held to the far right of its motion, however for the second part I'm not sure what to do with the phase constant. I know that the phase constant should probably be negative as it is pendulum motion to the left, however I'm not sure how to find it. I think if I can find the phase constant for the second part, use it to find the time, and add the times together I should get total time.

Any help is appreciated.
 
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  • #2
It would be best to work with 3 significant figures everywhere (0.12 rad isn't particularly accurate).

You write:
theta(t) = A * cos(omega * t + phi)
But theta is an angle and A is a distance in metres. . . .
It's the angular displacement that behaves simple-harmonically (i.e. varies sinusoidally)--there's usually no need to convert to a linear distance. In fact you could leave those angles in degrees; mathematically, degrees make as much sense as metres in this context, and they save work.

(Perhaps a simpler way to think about this part: What is the period of the motion? What fraction of that period is the time taken for the mass to swing from the extreme to the centre? --Think about what a sine or cosine curve looks like and what sorts of symmetry it has.)

For the second part, I think you're making it a bit more complicated than it needs to be. Remember the mass is in continuous sinusoidal motion from the time it's released.
 

1. What is pendulum motion?

Pendulum motion, also known as simple harmonic motion, is the motion of a swinging object that follows a repetitive pattern, back and forth around a central point.

2. What causes pendulum motion?

Pendulum motion is caused by the force of gravity acting on the object, as well as the object's potential energy and kinetic energy as it moves.

3. What is the formula for pendulum motion?

The formula for pendulum motion is T = 2π√(L/g), where T is the period (time for one complete swing), L is the length of the pendulum, and g is the acceleration due to gravity.

4. How does the length of a pendulum affect its motion?

The length of a pendulum directly affects its motion, as seen in the formula for pendulum motion. A longer pendulum will have a longer period, meaning it will take longer to complete one swing. A shorter pendulum will have a shorter period, meaning it will take less time to complete one swing.

5. What are some real-world applications of pendulum motion?

Pendulum motion is used in various applications, such as in clocks, metronomes, and amusement park rides. It is also used in scientific experiments to study the effects of gravity and motion. Additionally, pendulums are used in seismometers to measure earthquakes and in Foucault pendulums to demonstrate the rotation of the Earth.

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