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Interesting problem i came acrosss

by oneomega
Tags: acrosss, interesting
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oneomega
#1
Oct20-13, 06:33 AM
P: 16
okay,
there are two curves: curve1: y=a^x and curve2: b^x. what is the angle between them at their point of intersection. given that (a≠b).
My general method:
if i wanted angle b/w the curves y=x^2 and y=(x-2)^2, i would easily do it.
let A be angle b/w them,
then, tanA= [tan(m1)-tan(m2)]/1-tanm1.tanm2
can be used at their point of intersection.this is what my textbook says. but the problem with a^x and b^x is that I CANNOT FIND THE POINT OF INTERSECTION. which brings me to the very basic question, how can we find pt of intersection of curves like this?
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oneomega
#2
Oct20-13, 06:35 AM
P: 16
a small addendum, what i actually mean by angle b/w curves is the angle b/w their tangents at that point.
arildno
#3
Oct20-13, 06:38 AM
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P: 12,016
a^(x)=b^(x)-->(a/b)^x=1.
What does that tell you x must be, when "a" does not equal "b"?

oneomega
#4
Oct20-13, 06:49 AM
P: 16
Interesting problem i came acrosss

you tell me, is there something wrong with this problem?
oneomega
#5
Oct20-13, 06:50 AM
P: 16
beacuse, at the same x point, a and b has to be equal to get you to the same y value as the equation suggests
oneomega
#6
Oct20-13, 06:51 AM
P: 16
oh wait, i got it, x mustt be zero, so that for diff values of a and b, they get you the same y value.
i got it now.
arildno
#7
Oct20-13, 06:52 AM
Sci Advisor
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PF Gold
P: 12,016
That's right!

Both functions equal 1 when x=0
oneomega
#8
Oct20-13, 06:52 AM
P: 16
i'm not this dumb usually, its just that i got stuck here. thanks a lot.


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