Ensemble average in quantum computing

In summary, to obtain a result from a quantum computer, measurement is necessary to collapse the quantum state. This can be achieved by measuring a large ensemble average of the computed result, such as using NMR to measure billions of spins. The minimum number of ensembles required for a 'good' result is not specified. For a system with n qubits, assuming O(1) ensembles are required for one qubit, the number of ensembles needed for the same accuracy should be O(n) or possibly O(2^n). However, if the latter is true, then the potential of quantum computing is still questionable. There is no fixed minimum number for obtaining a good enough result, as it depends on the desired accuracy level. This
  • #1
morphemera
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In the last step to get result from a quantum computer, measurement is required to collapse the quantum state. This can be done by the measuring a large ensemble average of same computed result. One realization I know is to use NMR to measure billions of spin. So, what is the minimum number of ensembles are required to get a 'good' result?

Furthermore, suppose the number of one qubit requires O(1) ensemble, how many ensembles are required for n qubits system to have same accuracy? I suppose the answer should be O(n), but if it is O(2^n), then the realization of quantum computer still seems useless to me. Any explanation of the answer?
 
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  • #2
Is there a minimum number as such?

Let me ask you this: What's a good enough number of coin flips to see almost half the flips are heads?

You are talking about an accuracy in your second question, how much accuracy are you aiming for?

My point is there's no fundamental minimum. It's exactly like a coin toss experiment, nothing peculiar to quantum computing here, in this context.
 
  • #3


I can confirm that the concept of ensemble average is crucial in quantum computing. In order to obtain a result from a quantum computer, it is necessary to collapse the quantum state through measurement. This is often achieved by taking an average of multiple measurements on the same quantum system.

The minimum number of ensembles required to obtain a 'good' result may vary depending on the specific system and experiment being performed. However, in general, a larger number of ensembles will lead to a more accurate result. This is because the quantum state is inherently probabilistic, and by taking an average of multiple measurements, we can reduce the effects of random noise and errors.

If we consider the number of ensembles required for a system with n qubits, the answer is indeed O(n). This means that the number of ensembles needed will increase linearly with the number of qubits. This is a significant improvement compared to the classical computers, where the number of ensembles required would be O(2^n) for the same level of accuracy.

It is important to note that the realization of a quantum computer is not useless even if the number of ensembles required for n qubits is O(2^n). This is because the computational power of a quantum computer is not solely determined by the number of ensembles, but also by the principles of superposition and entanglement that allow for exponentially faster calculations compared to classical computers.

In conclusion, the ensemble average is a fundamental aspect of quantum computing and plays a crucial role in obtaining accurate results. The number of ensembles required for a good result is typically proportional to the number of qubits in the system, making quantum computers a promising technology for solving complex problems.
 

1. What is the ensemble average in quantum computing?

The ensemble average in quantum computing is a statistical measure that describes the expected outcome of a quantum computation. It takes into account the probabilities of all possible results and gives a single value that represents the average result.

2. How is the ensemble average calculated in quantum computing?

The ensemble average is calculated by taking the sum of all possible outcomes multiplied by their respective probabilities. This result is then divided by the total number of possible outcomes. In mathematical terms, it can be expressed as ∑xP(x), where x represents each possible outcome and P(x) represents its probability.

3. What is the significance of the ensemble average in quantum computing?

The ensemble average is significant because it allows us to predict the behavior of a quantum system even when we cannot know the exact outcome of a single measurement. It is also a key factor in understanding the performance and efficiency of quantum algorithms.

4. Can the ensemble average be used to measure the accuracy of a quantum computation?

Yes, the ensemble average can be used to measure the accuracy of a quantum computation. If the ensemble average of a quantum computation is close to the expected result, then it can be considered accurate. However, it should be noted that the ensemble average alone is not enough to determine the accuracy of a quantum computation and other factors such as error rates should also be taken into consideration.

5. How does the concept of ensemble average differ from classical computing?

In classical computing, the average of a set of values is simply the sum of all values divided by the number of values. However, in quantum computing, the ensemble average takes into account the probabilistic nature of quantum systems and is calculated using a different formula. Additionally, classical computing deals with deterministic systems while quantum computing deals with probabilistic systems, making the concept of ensemble average more relevant in quantum computing.

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