no of roots of a equation

arildno

And the integers break the rule basic for the naturals:
"There exists a LEAST number".

The rationals break with the fundamental rule of integers that says:
"There exists a number "a", so that adding or subtracting "a" from an integer (some number of times) will yield any other integer"

Whar was your point again?

pwsnafu

Instead of using the ^ symbol, I recommend using the superscript option of the forum, so it looks like ∫(x²+2)⁵ dx.

There are two methods you can use. The first is the binomial formula and expand out the brackets. Then integrate term by term. The only thing to be careful is calculating the coefficients, but a good calculator can take care of that.

The other option is factorise into ##\int(x^2+2)^5 \, dx = \int (x+i\sqrt2)^5(x-i\sqrt2)^5\,dx## and use integration by parts.