| New Reply |
Z-Boson reasonance and the number of neutrino varieties |
Share Thread | Thread Tools |
| Jan18-13, 05:27 PM | #1 |
|
|
Z-Boson reasonance and the number of neutrino varieties
I've read that the experimental results of Z-Boson resonance confirm the theoretical expectations that there are 3-types of Neutrinos, not 2 or 4.
How are these theoretical expectations calculated? I.e. how does the number of neutrino varieties affect Z-boson resonance? Thank you |
| PhysOrg.com |
physics news on PhysOrg.com >> Promising doped zirconia >> New X-ray method shows how frog embryos could help thwart disease >> Bringing life into focus |
| Jan18-13, 06:22 PM | #2 |
|
Mentor
|
Does http://en.wikipedia.org/wiki/Neutrino#Types answer your question? If not, can you be more specific as to what you are looking for?
|
| Jan21-13, 01:49 AM | #3 |
|
|
At the LEP experiment Z bosons were produced through colliding electrons and positrons. This was a very clean experiment, unlike the LHC, allowing the properties of the Z boson to be studied to high precision. The presence of the Z boson shows up as a peak in the total cross-section as a function of center of mass energy with the peak located at ~91 GeV corresponding to the mass of the Z boson (there is a nice plot of this on p711 fig.20.5 of Peskin & Schroeder). By measuring the Z peak very carefully they can determine the total width (##\Gamma_{tot}##) and the cross-section at the peak (##\sigma_{peak}##).
The total Z width ##\Gamma_{tot}## is actually made up of two parts. The first is the visible part ##\Gamma_{vis}## made up of decays to charged leptons and hadrons and this is related to the observed peak cross-section ##\sigma_{peak}##. The second is the invisible part ##\Gamma_{inv}## made up of decays to neutrinos which are not observed in the experiment. This second part can be determined by taking ##\Gamma_{tot}-\Gamma_{vis}=\Gamma_{inv}=N_\nu\Gamma(Z\to \nu\overline{\nu})## where ##N_\nu## is the number of active neutrinos. Notice it is "active" neutrinos that matter not the number of neutrinos as there might be "sterile" neutrinos which the Z doesn't decay to. Putting it all together we can get ##N_\nu## from $$N_\nu = (\Gamma_{tot}-\Gamma_{vis})/\Gamma(Z\to \nu\overline{\nu})$$ and the result is very close to ##N_\nu=3##. You can try to look at chapter 20 of Peskin & schroeder and in particular do the problems 20.2 and 20.3 on p 728 which will give you a good understanding of the Z resonance and how it relates to the number of active neutrinos. |
| Jan22-13, 07:06 PM | #4 |
|
|
Z-Boson reasonance and the number of neutrino varieties
This does help a lot. Thanks Vanadium and jkp.
|
| New Reply |
| Thread Tools | |
Similar Threads for: Z-Boson reasonance and the number of neutrino varieties
|
||||
| Thread | Forum | Replies | ||
| Higgs boson and neutrino mass | High Energy, Nuclear, Particle Physics | 8 | ||
| so does the Higg field give the neutrino mass, and can neutrino velocity change? | High Energy, Nuclear, Particle Physics | 5 | ||
| does neutrino oscillation from electron neutrino to muon neutrino conserve energy? | High Energy, Nuclear, Particle Physics | 4 | ||
| INTRO TO PHYSICS: Impedence, pitch, vibration, reasonance... Please Help! | Introductory Physics Homework | 5 | ||
| Neutrino as alternative to Higgs boson | High Energy, Nuclear, Particle Physics | 2 | ||