Electron Exclusion via EIT/CPT?

jaketodd

To simplify: You're still talking about rendering an EIT/CPT effect on the electron itself, when I am talking about the much-less-energetic "home" the 6th electron would have in the molecule. I am talking about rendering EIT/CPT on the energy level configuration; not on the electron itself. Without its place to settle, the electron cannot join the molecule.

jaketodd

I'm going to start another thread with a similar question. Thank you for your help thus far. I would like this thread to continue. I'll put the new one in the Quantum Physics category just like this one.

Jake

Zarqon

I'm pretty sure the crucial point that makes you confused is that you don't realize that a "dark state" is simple a completely normal superposition state, there's nothing magical or special to it. And there is no reason why an atom or molecule in a normal superposition state could not absorb an electron (if the situation at large is such that it could).

A dark state only becomes dark when paired with the light (of the right phase) that created it. The dark state is atom PLUS light, not the atom by itself, and thus you cannot "close the door" on the atom, because you only close it for that particular light, not for any other light, and not for electrons.

For further experimental proof of this, see the typical EIT spectra. The transmission peaks in EIT spectra (where the atom is dark) are typically very narrow. This means that light at just a slightly different frequency than what created it, is NO LONGER a dark state. It should then be obvious that something completely different, like electrons are definately not going to see a dark state.