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freefalling said:It doesn't say, the graph is all I got :( Thank you for your help!
freefalling said:Yes :( like why it's 16-2 but not 16-6 (thats what makes sense to me)
A velocity-time graph is a graphical representation of an object's motion, showing the relationship between its velocity (speed and direction) and time. The slope of the graph represents the object's acceleration, while the area under the graph represents the object's displacement.
To find the total displacement on a velocity-time graph, you need to calculate the area under the graph. This can be done by dividing the graph into smaller shapes (triangles, rectangles, etc.) and calculating their individual areas. Then, add all the individual areas together to get the total displacement.
A positive area on a velocity-time graph represents a positive displacement, meaning the object is moving in the positive direction. A negative area represents a negative displacement, meaning the object is moving in the negative direction (opposite of positive).
The slope of a velocity-time graph represents the object's acceleration. A steeper slope indicates a higher acceleration, while a flatter slope indicates a lower acceleration. A horizontal line (zero slope) represents a constant velocity, and a vertical line (infinite slope) represents an instantaneous change in velocity (such as during free fall).
Yes, you can determine an object's displacement at a specific time on a velocity-time graph by finding the area under the graph up to that specific time. This is known as the object's displacement at a specific time interval. However, to find the total displacement over a specific time period, you need to calculate the area under the entire graph.