Space-time transformations with different shape

In summary: The main difference is that in Tangherlini coordinates the metric is flat, while in SR it is curved.In summary, the Tangherlini equations introduce a coordinate system for relative motion that is not orthogonal, does not use the relativity of simultaneity, and is more complicated to use than the usual SR inertial coordinates.
  • #1
bernhard.rothenstein
991
1
I find in the literature the following transformation equations for the space-time coordinates
x'=g(x-vt)
t'=t/g
g=gamma.
Please tell me what do they bring new in the approach to SRT?
Thanks
 
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  • #2
How are those different from the usual formulas?
 
  • #3
bernhard.rothenstein said:
I find in the literature the following transformation equations for the space-time coordinates
x'=g(x-vt)
t'=t/g
g=gamma.
Please tell me what do they bring new in the approach to SRT?
Thanks

The second equation is true only for a body stationary in the ref frame S', so that x' = 0 and x = vt. If you already have the Lorentz transforms, those you have written are just a particular case and don't bring anything new.
 
  • #4
bernhard.rothenstein said:
I find in the literature the following transformation equations for the space-time coordinates
x'=g(x-vt)
t'=t/g
g=gamma.
Please tell me what do they bring new in the approach to SRT?
Thanks
Are you sure about the t'=t/g?
Because if you are, this is different from a particularization of the Lorentz transforms. These are the so called Tangherlini transforms, a variant of relativity. See here.

Tangherlini has his own theory, the absence of the term in vx/c^2 in his time transform results into absolute simultaneity. There is a claim that his theory is experimentally indistinguishable from SR.
 
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  • #5
bernhard.rothenstein said:
I find in the literature the following transformation equations for the space-time coordinates
x'=g(x-vt)
t'=t/g
g=gamma.
Please tell me what do they bring new in the approach to SRT?
Thanks
The second equation is not a coordinate transformation for SR since it does not introduce the relativity of simultaneity. It could be that the second one is intended to be an interval transformation (e.g. maybe it means dt'=dt/g)
 
  • #6
lorentz transformations

1effect said:
Are you sure about the t'=t/g?
Because if you are, this is different from a particularization of the Lorentz transforms. These are the so called Tangherlini transforms, a variant of relativity. See here.

Tangherlini has his own theory, the absence of the term in vx/c^2 in his time transform results into absolute simultaneity. There is a claim that his theory is experimentally indistinguishable from SR.
Thanks for your help. Please tell me if you aggree with:
1. The Lorentz-Einstein transformations hold only in the case when the times they involve are displayed by clocks synchronized a la Einstein t(E) and t'(E) respectively.
2. They also hold when we replace t(E) and t'(E) with other linear combinations of time and space coordinates as in the case of a radar detection or in the case of the photographic detection.
 
  • #7
bernhard.rothenstein said:
I find in the literature the following transformation equations for the space-time coordinates
x'=g(x-vt)
t'=t/g
g=gamma.
Please tell me what do they bring new in the approach to SRT?
Thanks
This transformation is sometimes called the Tangherlini transform and was also studied by Mansouri and Sexl in 1976.

(Note: everything that follows assumes no gravity, i.e. a flat spacetime.)

(x,t) is a standard inertial frame in which light speed is isotropic (the same in all directions), which can be called the "aether frame" in this context. (x',t'), defined by the above, defines a coordinate system for an observer moving at speed v relative to the aether frame. Tangherlini coordinates exhibit the same length-contraction and time-dilation properties as the usual SR inertial coordinates defined by the Lorentz transform, but they use a different definition for simultaneity (or to put it another way, they use a different synchronisation gauge).

In the context of the mathematics of GR (manifolds), Tangherlini coordinates are a valid coordinate chart, but the axes are not orthogonal. The metric, though flat, is not diagonalised in Tangherlini coordinates. Equations converted to Tangherlini coordinates are generally more complicated, the Tangherlini-speed of light is not isotropic, and momentum is not an isotropic function of Tangherlini-velocity. (If I haven't made a silly mistake, I think the metric is ds2 = dx'2/g2 - c2 dt'2 - 2vc dx' dt'.) All of these facts make Tangherlini coordinates rather painful to use compared with the usual SR inertial coordinates.

The main reason why advocates of Tangherlini coordinates like them is because they use absolute simultaneity. Events that are simultaneous in the aether frame are simultaneous in all other Tangherlini frames. So those who have some philosophical objection to relative simultaneity, or who can't grasp the concept, or who have other reasons for postulating the existence of an aether, will find comfort in the Tangherlini approach and the fact that there's nothing demonstrably wrong with it. His theory is "experimentally indistinguishable from SR" because it's actually the same theory transformed into a non-standard coordinate system.

What is unfortunate is that to use Tangherlini coordinates you have to determine an aether frame and you need to know the velocity of your own Tangherlini frame relative to the aether. An observer inside a sealed box, moving inertially relative to a postulated aether, would be unable to determine their speed relative to the aether and therefore unable to construct any Tangherlini coordinates.

But, in fact, it doesn't matter which frame you choose for your aether frame. Just choose any inertial observer and define an inertial frame using the Einstein synchronisation convention, and derive all the other Tangherlini frames from that. The fact that a privileged aether frame is postulated, but you are free to choose any such frame you like, seems a philosophical defect, compared with Einstein's formulation of SR.


bernhard.rothenstein said:
Please tell me if you aggree with:
1. The Lorentz-Einstein transformations hold only in the case when the times they involve are displayed by clocks synchronized a la Einstein t(E) and t'(E) respectively.
Yes. That is, t(E) is Einstein-synchronized to one observer's clock and t'(E) is Einstein-synchronized to the other observer's clock.

bernhard.rothenstein said:
Please tell me if you aggree with:
2. They also hold when we replace t(E) and t'(E) with other linear combinations of time and space coordinates as in the case of a radar detection or in the case of the photographic detection.
No, if you transform (x,t) and (x',t') into something else, the Lorentz-transformation equations will transform into something else. E.g. try substituting r' = t' + x'/c, s' = t' - x'/c, t = (r + s)/2, x = c(r - s)/2 into the Lorentz transform equations and see what you get for (r',s') in terms of (r,s). (The radar-coordinate version of the Lorentz transform.)


Reference:

R Mansouri & R U Sexl (1977), http://scholar.google.com/scholar?h...nchronization"+author:r-mansouri&btnG=Search", General Relativity and Gravitation, Springer, Vol 8, No 7, pp.497-513.
 
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  • #8
Lorentz transformation

No, if you transform (x,t) and (x',t') into something else, the Lorentz-transformation equations will transform into something else. E.g. try substituting r' = t' + x'/c, s' = t' - x'/c, t = (r + s)/2, x = c(r - s)/2 into the Lorentz transform equations and see what you get for (r',s') in terms of (r,s). (The radar-coordinate version of the Lorentz transform.)

Thanks for your help. I have studied a paper devoted to relativistic navigation mimicking the maritime one. The author proposes a navigation convention according to which observers in the I' frame measure distances on a chart devised by observers in I and times using a clock comoving with the ship. What the observers in I' need are the time attributed by observers from I (t) and their space coordinate in their I' frame. They obtain transformation equations which express t(x,t') and x'(x,t'). Do you see there some thing wrong.
Leubner quoted below presents an "everyday clock synchronization procedure" consisting in the fact that an observer in I has at his disposal his wrist watch Eintein synchronized with the other clocks which displays t(E) and the information brought by the radio signal
t(r) equal to the reading of a clock from I located at its origin O when the radio signal was emitted. We have in an one space dimension
t(E)=t(r)+x/c.
Replacing that value in the Lorentz transformations we obtain transformation equations for x',t(E) and t'(r). The result is absolute simultaneity. From a practical point of view observers from I can express x', t'(E) and t'(T) as a function of the physical quantities they can measure x t(E), t(t). Is there something wrong? Is the job well done?
The authors solve the problem in a complicated way using the concept of "base vectors".
Regards
I Elementary relativity with I 'everyday' clock synchronization
C Leubnert, K Aufingert and P KrummS
t Physics Education Group, lnstitut fur Theoretische Physik, Leopold-Franzens-Universitat Innsbruck,
Technikerstr. 25, A-6020 Innsbruck, Austria
$Department of Physics, University of Natal
 
  • #9
bernhard.rothenstein said:
I have studied a paper devoted to relativistic navigation mimicking the maritime one. The author proposes a navigation convention according to which observers in the I' frame measure distances on a chart devised by observers in I and times using a clock comoving with the ship. What the observers in I' need are the time attributed by observers from I (t) and their space coordinate in their I' frame. They obtain transformation equations which express t(x,t') and x'(x,t'). Do you see there some thing wrong.
It's an unusual way to do things (mixing primed and unprimed coordinates) but, assuming the author makes no mistakes, there's nothing actually wrong with this and it could be of some practical use. A "moving" observer may be able to measure their distance on a "static" scale but only have access to their own "moving" clock, for example. (Of course, the words "static" and "moving" are both relative to a single inertial frame.) Dividing "static" distance by "moving" (i.e. proper) time you get something called "celerity" or "proper velocity" (see this post).

bernhard.rothenstein said:
Leubner quoted below presents an "everyday clock synchronization procedure" consisting in the fact that an observer in I has at his disposal his wrist watch Eintein synchronized with the other clocks which displays t(E) and the information brought by the radio signal
t(r) equal to the reading of a clock from I located at its origin O when the radio signal was emitted. We have in an one space dimension
t(E)=t(r)+x/c.
Replacing that value in the Lorentz transformations we obtain transformation equations for x',t(E) and t'(r). The result is absolute simultaneity. From a practical point of view observers from I can express x', t'(E) and t'(T) as a function of the physical quantities they can measure x t(E), t(t). Is there something wrong? Is the job well done?
The authors solve the problem in a complicated way using the concept of "base vectors".
Regards
I Elementary relativity with I 'everyday' clock synchronization
C Leubnert, K Aufingert and P KrummS
t Physics Education Group, lnstitut fur Theoretische Physik, Leopold-Franzens-Universitat Innsbruck,
Technikerstr. 25, A-6020 Innsbruck, Austria
$Department of Physics, University of Natal

For the benefit of other readers I'll reproduce the abstract:

C Leubner said:
http://www.iop.org/EJ/abstract/0143-0807/13/4/004/

"Elementary relativity with 'everyday' clock synchronization"

C Leubner, K Aufinger and P Krumm 1992 Eur. J. Phys. 13 170-177 doi:10.1088/0143-0807/13/4/004

Abstract. Although the importance of clock synchronization for relativity is discussed from time to time in the educational literature, the fact that different synchronization conventions imply different coordinizations of spacetime with ensuing changes of the form of possibly all coordinate-dependent quantities, has neither entered textbooks nor undergraduate physics education. As a consequence, there is a widespread belief among students that the familiar form of coordinate-dependent quantities like the measured velocity of light, the Lorentz transformation between two observers, 'addition of velocities', 'time dilation', 'length contraction', '[tex]E = mc^2 \gamma[/tex]', which they assume under the standard clock synchronization, is relatively proper. In order to demonstrate that this is by no means so, the paper studies the consequences of a non-standard synchronization, and it is shown that drastic changes in the appearance of all these quantities are thus induced. For example, the phrases 'moving clocks go slow', and 'simultaneity is relative', which are usually considered as intrinsic features of relativity, turn out to be no longer true, whereas all coordinate-independent quantities remain of course indifferent to such a change in coordinization. Although Einstein's standard convention of clock synchronization enjoys distinct advantages over the 'everyday' method, the message clearly conveyed is that in the teaching of elementary relativity much more stress should be laid on the intrinsic (coordinate-independent) features of spacetime.
It was only a few years ago, soon after I started using this forum, that I realized that some of the standard relativistic effects, as described above, are coordinate-dependent and that other coordinate systems were permissible.

The point the authors are making is that there are lots of different coordinate systems to choose from apart from the standard "Einstein-synced" coordinates. Einstein coords are arguably the best coords but they are not the only coords, and it is educational to consider some of the other possibilities. The "everyday" coords that the authors define are one possibility.

The "radar coordinates" (e,r) which I defined in this post are another possibility. These are unusual because their two axes are not timelike and spacelike respectively, like most systems, but both null. (For mathematicians, radar coordinates are particularly interesting because they diagonalise the Lorentz transform; the two coord directions are eigenvectors and the k and k-1 red- and blue-shift Doppler factors are the eigenvalues.)

Time and space coordinates [tex](t(\epsilon), x)[/tex] can be defined from (e,r) by

[tex]t(\epsilon) = e + \epsilon(r - e) = (1 - \epsilon)e + \epsilon r[/tex]

[tex]x = c(r - e)/2[/tex]

(Sorry: you'll need to look closely at the above equations to see the difference between "epsilon" and "e".)

You have a choice of [tex]\epsilon[/tex]:

  • Standard Einstein-synced coordinates result when [tex]\epsilon[/tex] = ½. (t(E) in your notation.)
  • Leubner et al’s "everyday" coords result when [tex]\epsilon[/tex] = 0. (t(r) in your notation.)
  • Tangherlini coords (which I discussed in an earlier post in this thread) result when [tex]\epsilon[/tex] = ½(1 + v/c), where v is the supposed velocity of the observer relative to a postulated aether.

I think it is useful to be aware of these different coord systems, to help understand which relativistic effects are "intrinsic" (coord independent) – e.g. the twin "paradox" -- and which are not. However I’m not sure whether it’s a good idea to present all this to someone learning relativity for the first time; it might just confuse them.

I have a particular fondness for radar coordinates because of how, with k-calculus, they can be used to derive many results with quite simple proofs, and some without even having to define "simultaneity". The concept of "relative simultaneity" seems to be what most people have most difficulty understanding when learning relativity.

It is not clear to me whether Leubner’s "everyday" coords help with the original navigation problem. Nor am I convinced that using "base vectors" (I would call them "unit basis vectors") is the easiest method. I would think you just need to write down all the relevant equations to convert from one coord system to another and then it’s just maths (algebra) to solve them.

I’m not sure I’ve answered your question. Does any of this help you?
 
  • #10
DrGreg said:
(If I haven't made a silly mistake, I think the metric is ds2 = dx'2/g2 - c2 dt'2 - 2vc dx' dt'.)
Nobody spotted I did make a silly mistake. The correct formula should be

ds2 = dx'2/g2 - c2 dt'2 + 2v dx' dt'

(I hope.)
 
  • #11
lorentz transformations

DrGreg said:
It's an unusual way to do things (mixing primed and unprimed coordinates) but, assuming the author makes no mistakes, there's nothing actually wrong with this and it could be of some practical use. A "moving" observer may be able to measure their distance on a "static" scale but only have access to their own "moving" clock, for example. (Of course, the words "static" and "moving" are both relative to a single inertial frame.) Dividing "static" distance by "moving" (i.e. proper) time you get something called "celerity" or "proper velocity" (see this post).



For the benefit of other readers I'll reproduce the abstract:

It was only a few years ago, soon after I started using this forum, that I realized that some of the standard relativistic effects, as described above, are coordinate-dependent and that other coordinate systems were permissible.

The point the authors are making is that there are lots of different coordinate systems to choose from apart from the standard "Einstein-synced" coordinates. Einstein coords are arguably the best coords but they are not the only coords, and it is educational to consider some of the other possibilities. The "everyday" coords that the authors define are one possibility.

The "radar coordinates" (e,r) which I defined in this post are another possibility. These are unusual because their two axes are not timelike and spacelike respectively, like most systems, but both null. (For mathematicians, radar coordinates are particularly interesting because they diagonalise the Lorentz transform; the two coord directions are eigenvectors and the k and k-1 red- and blue-shift Doppler factors are the eigenvalues.)

Time and space coordinates [tex](t(\epsilon), x)[/tex] can be defined from (e,r) by

[tex]t(\epsilon) = e + \epsilon(r - e) = (1 - \epsilon)e + \epsilon r[/tex]

[tex]x = c(r - e)/2[/tex]

(Sorry: you'll need to look closely at the above equations to see the difference between "epsilon" and "e".)

You have a choice of [tex]\epsilon[/tex]:

  • Standard Einstein-synced coordinates result when [tex]\epsilon[/tex] = ½. (t(E) in your notation.)
  • Leubner et al’s "everyday" coords result when [tex]\epsilon[/tex] = 0. (t(r) in your notation.)
  • Tangherlini coords (which I discussed in an earlier post in this thread) result when [tex]\epsilon[/tex] = ½(1 + v/c), where v is the supposed velocity of the observer relative to a postulated aether.

I think it is useful to be aware of these different coord systems, to help understand which relativistic effects are "intrinsic" (coord independent) – e.g. the twin "paradox" -- and which are not. However I’m not sure whether it’s a good idea to present all this to someone learning relativity for the first time; it might just confuse them.

I have a particular fondness for radar coordinates because of how, with k-calculus, they can be used to derive many results with quite simple proofs, and some without even having to define "simultaneity". The concept of "relative simultaneity" seems to be what most people have most difficulty understanding when learning relativity.

It is not clear to me whether Leubner’s "everyday" coords help with the original navigation problem. Nor am I convinced that using "base vectors" (I would call them "unit basis vectors") is the easiest method. I would think you just need to write down all the relevant equations to convert from one coord system to another and then it’s just maths (algebra) to solve them.

I’m not sure I’ve answered your question. Does any of this help you?

Thank you very much for your answer which is of big help in finishing my paper in which I try to simplify Leubner's approach making it available to a large number of interested people. I started with the Lorentz transformations in their standard shape, replacing t(E)
wity t(T)+x/c recovering all Leubner's results and even adding to them new ones showing that as expected t(T) and t"(T) are related by the Doppler effect which is clock synchronization independent. Receiving e-mail addresses I could send to solicitors a draft
of it for a critical inspection.
Thanks again DrGrieg. Your help is a good reason for me to visit the Forum learning from people who know more then I do, sharing with generosity their knowledge.
 
  • #12
DrGreg said:
Nobody spotted I did make a silly mistake. The correct formula should be

ds2 = dx'2/g2 - c2 dt'2 + 2v dx' dt'

(I hope.)

I think the metric might still be wrong.I am getting:
From:
[tex]x=g(x'-vt')[/tex]
[tex]t=t'/g[/tex]

Producing:
[tex]ds^2=x^2-(ct)^2=g^2(x'-vt')^2-(ct'/g)^2[/tex]

So:

[tex]ds^2=g^2(dx')^2-2vg^2dx'dt'+(g^2v^2-(c/g)^2)(dt')^2[/tex]
 
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  • #13
1effect said:
I think the metric might still be wrong.I am getting:
From:
[tex]x=\gamma(x'-vt')[/tex]
[tex]t=t'/\gamma[/tex]

Producing:
[tex]ds^2=x^2-(ct)^2=\gamma^2(x'-vt')^2-(ct'/\gamma)^2[/tex]

So:

[tex]ds^2=\gamma^2(dx')^2-2v\gamma^2dx'dt'+(\gamma^2v^2-(c/\gamma)^2)(dt')^2[/tex]

In this thread I had the primed and unprimed coordinates the other way round! See post #1.
[tex]x'=\gamma(x-vt)[/tex]
[tex]t'=t/\gamma[/tex]
 
  • #14
DrGreg said:
In this thread I had the primed and unprimed coordinates the other way round! See post #1.
[tex]x'=\gamma(x-vt)[/tex]
[tex]t'=t/\gamma[/tex]

So, interchanging primed with unprimed you would get:

From:
[tex]x'=g(x-vt)[/tex]
[tex]t'=t/g[/tex]

Producing:
[tex]ds^2=x'^2-(ct')^2=g^2(x-vt)^2-(ct/g)^2[/tex]

So, the metric is:

[tex]ds^2=g^2(dx)^2-2vg^2dxdt+(g^2v^2-(c/g)^2)(dt)^2[/tex]

No?
 
  • #15
1effect said:
So, interchanging primed with unprimed you would get:

From:
[tex]x'=\gamma(x-vt)[/tex]
[tex]t'=t/\gamma[/tex]

Producing:
[tex]ds^2=dx'^2-(cdt')^2=\gamma^2(dx-vdt)^2-(cdt/\gamma)^2[/tex]

So, the metric is:

[tex]ds^2=\gamma^2(dx)^2-2v\gamma^2dxdt+(\gamma^2v^2-(c/\gamma)^2)(dt)^2[/tex]

No?
No. Remember what's what.

x & t are the Einstein coords in the "reference" frame. x' and t' are the Tangherlini coords in the "moving" frame. We know [tex]ds^2=dx^2-c^2dt^2[/tex] and we want to find the expression in terms of dx' and dt'.

(I added the T and E suffixes in other threads to avoid this confusion.)
 
  • #16
DrGreg said:
No. Remember what's what.

x & t are the Einstein coords in the "reference" frame. x' and t' are the Tangherlini coords in the "moving" frame. We know [tex]ds^2=dx^2-c^2dt^2[/tex] and we want to find the expression in terms of dx' and dt'.

(I added the T and E suffixes in other threads to avoid this confusion.)

Yes, in this case you obtain the metric in your original post:

[tex]ds^2=(x'/\gamma)^2+2vx't'-(ct')^2[/tex]Setting [tex]ds=0[/tex] produces the anisotropic speed of
[tex]\gamma^2(c-v)[/tex] and [tex]-\gamma^2(c+v)[/tex] (negative, as one would expect)

The two-way light speed in the "Tangherlini frame" comes to [tex]\gamma^2 v[/tex] . This doesn't look good, something isn't right
 
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  • #17
1effect said:
Yes, in this case you obtain the metric in your original post:

[tex]ds^2=(x'/\gamma)^2+2vx't'-(ct')^2[/tex]


Setting [tex]ds=0[/tex] produces the anisotropic speed of
[tex]\gamma^2(c-v)[/tex] and [tex]-\gamma^2(c+v)[/tex] (negative, as one would expect)
Yes.

1effect said:
The two-way light speed in the "Tangherlini frame" comes to [tex]\gamma^2 v[/tex] . This doesn't look good, something isn't right
The two-way speed isn't the average of the two one-way speeds. It's the total distance divided by total time; the two distances are the same but the two times are different. If you think about it long enough you will see that in fact the reciprocal of the two-way speed is the average of the reciprocals of the two one-way speeds.
 
  • #18
DrGreg said:
Yes.

The two-way speed isn't the average of the two one-way speeds. It's the total distance divided by total time; the two distances are the same but the two times are different. If you think about it long enough you will see that in fact the reciprocal of the two-way speed is the average of the reciprocals of the two one-way speeds.

Got it, thank you !

[tex]\frac{L}{c_{two-way}}=.5(\frac{L}{|c_+|}+\frac{L}{|c_-|})[/tex]

Great stuff, can you recommend a book on this material?
 
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  • #19
1effect said:
Got it, thank you !

[tex]\frac{L}{c_{two-way}}=.5(\frac{L}{|c_+|}+\frac{L}{|c_-|})[/tex]

Great stuff, can you recommend a book on this material?
I'm afraid not. This is stuff I've gradually picked up from a variety of online sources (including discussions on this forum) and my own calculations over the last 2 years.

Did you see this post in another thread? The link given there is well worth reading for a philosophical overview of different synchronisation conventions. It also gives lots of references, none of which I've checked yet. (EDIT: that link seems to be broken; try this instead: Stanford Encyclopedia of Philosophy - Conventionality of Simultaneity)

If you Google our site for "Mansouri Sexl", you'll find some old 2006 discussions around this subject, although there's a lot of stuff to wade through and you might not have the energy for it.

A more general Google (for "Mansouri Sexl", or "Tangherlini", or "Selleri", or "Generalised Galilean Transformation" will find a lot more, but some of that will be "crackpot" stuff claiming that this theory is an alternative (i.e. rival) theory to relativity and proves the existence of an aether. If you've followed this thread you should realize such claims are rubbish and all you are doing is relativity in a weird (viz. non-orthogonal) coordinate system.

There's a mention of Mansouri & Sexl on Wikipedia* here (put epsilon = 0, and a(v), b(v) the values quoted there). (*You can't always rely on Wikipedia, but that section looks OK, today!)
 
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  • #20
DrGreg said:
I'm afraid not. This is stuff I've gradually picked up from a variety of online sources (including discussions on this forum) and my own calculations over the last 2 years.

Did you see this post in another thread? The link given there is well worth reading for a philosophical overview of different synchronisation conventions. It also gives lots of references, none of which I've checked yet.

yes, I read it yesterday :-)

If you Google our site for "Mansouri Sexl", you'll find some old 2006 discussions around this subject, although there's a lot of stuff to wade through and you might not have the energy for it.

A more general Google (for "Mansouri Sexl", or "Tangherlini", or "Selleri", or "Generalised Galilean Transformation" will find a lot more, but some of that will be "crackpot" stuff claiming that this theory is an alternative (i.e. rival) theory to relativity and proves the existence of an aether. If you've followed this thread you should realize such claims are rubbish and all you are doing is relativity in a weird (viz. non-orthogonal) coordinate system.

There's a mention of Mansouri & Sexl on Wikipedia* here (put epsilon = 0, and a(v), b(v) the values quoted there). (*You can't always rely on Wikipedia, but that section looks OK, today!)

Thank you !
 
  • #21
DrGreg said:
It's an unusual way to do things (mixing primed and unprimed coordinates) but, assuming the author makes no mistakes, there's nothing actually wrong with this and it could be of some practical use. A "moving" observer may be able to measure their distance on a "static" scale but only have access to their own "moving" clock, for example. (Of course, the words "static" and "moving" are both relative to a single inertial frame.) Dividing "static" distance by "moving" (i.e. proper) time you get something called "celerity" or "proper velocity" (see this post).



For the benefit of other readers I'll reproduce the abstract:

It was only a few years ago, soon after I started using this forum, that I realized that some of the standard relativistic effects, as described above, are coordinate-dependent and that other coordinate systems were permissible.

The point the authors are making is that there are lots of different coordinate systems to choose from apart from the standard "Einstein-synced" coordinates. Einstein coords are arguably the best coords but they are not the only coords, and it is educational to consider some of the other possibilities. The "everyday" coords that the authors define are one possibility.

The "radar coordinates" (e,r) which I defined in this post are another possibility. These are unusual because their two axes are not timelike and spacelike respectively, like most systems, but both null. (For mathematicians, radar coordinates are particularly interesting because they diagonalise the Lorentz transform; the two coord directions are eigenvectors and the k and k-1 red- and blue-shift Doppler factors are the eigenvalues.)

Time and space coordinates [tex](t(\epsilon), x)[/tex] can be defined from (e,r) by

[tex]t(\epsilon) = e + \epsilon(r - e) = (1 - \epsilon)e + \epsilon r[/tex]

[tex]x = c(r - e)/2[/tex]

(Sorry: you'll need to look closely at the above equations to see the difference between "epsilon" and "e".)

You have a choice of [tex]\epsilon[/tex]:

  • Standard Einstein-synced coordinates result when [tex]\epsilon[/tex] = ½. (t(E) in your notation.)
  • Leubner et al’s "everyday" coords result when [tex]\epsilon[/tex] = 0. (t(r) in your notation.)
  • Tangherlini coords (which I discussed in an earlier post in this thread) result when [tex]\epsilon[/tex] = ½(1 + v/c), where v is the supposed velocity of the observer relative to a postulated aether.

I think it is useful to be aware of these different coord systems, to help understand which relativistic effects are "intrinsic" (coord independent) – e.g. the twin "paradox" -- and which are not. However I’m not sure whether it’s a good idea to present all this to someone learning relativity for the first time; it might just confuse them.

I have a particular fondness for radar coordinates because of how, with k-calculus, they can be used to derive many results with quite simple proofs, and some without even having to define "simultaneity". The concept of "relative simultaneity" seems to be what most people have most difficulty understanding when learning relativity.

It is not clear to me whether Leubner’s "everyday" coords help with the original navigation problem. Nor am I convinced that using "base vectors" (I would call them "unit basis vectors") is the easiest method. I would think you just need to write down all the relevant equations to convert from one coord system to another and then it’s just maths (algebra) to solve them.

I’m not sure I’ve answered your question. Does any of this help you?
Please let me know which kind of clock synchronization leads to the Edward's transformations?
Thanks.
 
  • #22
bernhard.rothenstein said:
Please let me know which kind of clock synchronization leads to the Edward's transformations?
Thanks.
I've only just discovered what an "Edward's transformation" is. I'll get back to you once I've read more about it.
 
  • #23
bernhard.rothenstein said:
Please let me know which kind of clock synchronization leads to the Edward's transformations?
Thanks.
According to Shen(1), the Edwards transform is

[tex]X' = K(X - VT)[/tex]
[tex]T'=K \left[ \left(1 + \frac {\lambda + \lambda'}{c} V \right) T + \left( \frac {\lambda^2 - 1}{c^2} V + \frac {\lambda - \lambda'}{c} \right) X \right] [/tex]
[tex] K = \frac {1} {\sqrt{(1 + \lambda V / c)^2 - V^2/c^2}} [/tex]​

(When [itex]\lambda = \lambda' = 0[/itex], this is just the Lorentz transform.)

If I have done my calculations correctly, these equations can be derived from Einstein-synced inertial coordinates (t,x) and (t',x') moving at relative velocity v, by setting

[tex]X = x[/tex]
[tex]T = t + \lambda x / c [/tex]
[tex]V = \frac {v}{1 - \lambda v / c} [/tex]​

and similar equations for primed coordinates.

This, in turn, corresponds to setting Reichenbach's [itex]\epsilon = (1 + \lambda)/2[/itex].

I haven't double checked my calculations, I may have made a mistake.

Reference

(1) Shen, J.Q. (2005), "Lorentz, Edwards transformations and the principle of permutation invariance".
 
  • #24
DrGreg said:
The "radar coordinates" (e,r) which I defined in this post are another possibility.

These coordinates (multiplied by [itex]1/\sqrt{2}[/itex]) are popular in string theory, where they are called light-cone coordinates, and are denoted [itex]x^+[/itex] and [itex]x^-[/itex] there.
 
  • #25
DrGreg said:
[tex]X = x[/tex]
[tex]T = t + \lambda x / c [/tex]​
I've now seen Edwards' original paper (1). Following his method, I see a very easy way to prove my result: simply put V=0 and [itex]\lambda' = 0[/itex] into the transform itself!

I did make one mistake, though: for consistency with my previous post #9, Reichenbach's epsilon should really be [itex]\epsilon = (1 - \lambda)/2[/itex].

To put this into context, the Edwards' transform is between two coordinate systems which do not necessarily use Einstein's sync convention, where [itex]\lambda = 1 - 2\epsilon[/itex] and [itex]\lambda' = 1 - 2\epsilon'[/itex] parameterise the synchronisation conventions chosen in each of the two coordinate systems, zero representing Einstein synchronisation.

In a private message to me, Bernhard pointed out that some other equations (29) in Edwards' paper correspond to the "Leubner everyday coordinates" mentioned earlier in this thread (and others -- Google bernhard.rothenstein Leubner site:physicsforums.com if you are interested). In reply, I point out these are the special case where [itex]\lambda = \lambda' = 1[/itex], i.e. where Reichenbach's [itex]\epsilon = 0[/itex], and where the one-way coordinate-speed of light in the positive x direction is infinite for both unprimed and primed observers.

As an aside, note quite a significant result of section IV of Edwards' paper: in such circumstances (infinite light speed in the positive x direction), the one-way coordinate-speed of light in the orthogonal yz-plane must be isotropic (=c) in order that the "four-way speed of light" round a non-planar quadrilateral is isotropic as experiment demands. So Leubner's sync convention can be applied only in one dimension.


(Sorry, I will be off-line for the next week and a half, and will not be able to reply for a while.)


Reference

Edwards, W.F. (1963), http://link.aip.org/link/?AJPIAS/31/482/1 , American Journal of Physics 31, Issue 7, pp. 482-489.
 
Last edited by a moderator:
  • #26
Re. anisotropy of the coordinate system induced by synchyronization procedure

bernhard.rothenstein said:
Thank you very much for your answer which is of big help in finishing my paper in which I try to simplify Leubner's approach making it available to a large number of interested people. I started with the Lorentz transformations in their standard shape, replacing t(E)
wity t(T)+x/c recovering all Leubner's results and even adding to them new ones showing that as expected t(T) and t"(T) are related by the Doppler effect which is clock synchronization independent. Receiving e-mail addresses I could send to solicitors a draft
of it for a critical inspection.
Thanks again DrGrieg. Your help is a good reason for me to visit the Forum learning from people who know more then I do, sharing with generosity their knowledge.

Do you aggree with the following extension of one of yours remarkable definitions:
The anisotropy is not a property of spacetime, but a property of the coordinate system,,,,,,, conferred by the synchronization procedure. Different synchronization procedures confer different ansotropies
 
  • #27


bernhard.rothenstein said:
Do you aggree with the following extension of one of yours remarkable definitions:
The anisotropy is not a property of spacetime, but a property of the coordinate system,,,,,,, conferred by the synchronization procedure. Different synchronization procedures confer different ansotropies
I rry to extend the statement above with

The anisotropy is not a property of spacetime, but a property of the coordinate system,,,,,,, conferred by the synchronization procedure. Different synchronization procedures confer different ansotropies. The different from Einsten's clock synchronization in a given inertial reference frame becomes anisotropic only when detected from another inertial reference frame.
 
  • #28


bernhard.rothenstein said:
I rry to extend the statement above with

The anisotropy is not a property of spacetime, but a property of the coordinate system,,,,,,, conferred by the synchronization procedure. Different synchronization procedures confer different ansotropies.
I suppose so, yes.

We are talking about anisotropy of the (1-way) speed of light. Speed is a coordinate-dependent concept, and in particular "1-way speed" is a synchronisation-dependent concept, so any talk of anisotropic speed must imply a coordinate system. In my way of thinking, "spacetime" is something that exists independently of any coordinate system. You can have lots of different coordinate systems all describing the same spacetime. I suppose some other people might describe them as different spacetimes, but I don't think (in my limited experience) that is the modern "geometric" view of relativity.
bernhard.rothenstein said:
The different from Einsten's clock synchronization in a given inertial reference frame becomes anisotropic only when detected from another inertial reference frame.
I don't understand that sentence!

Whether or not light speed is isotropic should be clear from any measurements you make in the coordinate system -- or from the definition of the coordinates themselves -- you don't necessarily need to compare with Einstein-synced coords to detect anisotropy. For example, in the Leubner "everyday" sync (Reichenbach's [itex]\epsilon = 0[/itex]), the fact that light-speed is infinite in one direction is automatic by definition, and in other directions it cannot be infinite due to the experimental fact that 2-way (and n-way) speed of light is always isotropic.
 
  • #29


DrGreg said:
I suppose so, yes.

We are talking about anisotropy of the (1-way) speed of light. Speed is a coordinate-dependent concept, and in particular "1-way speed" is a synchronisation-dependent concept, so any talk of anisotropic speed must imply a coordinate system. In my way of thinking, "spacetime" is something that exists independently of any coordinate system. You can have lots of different coordinate systems all describing the same spacetime. I suppose some other people might describe them as different spacetimes, but I don't think (in my limited experience) that is the modern "geometric" view of relativity.
I don't understand that sentence!

Whether or not light speed is isotropic should be clear from any measurements you make in the coordinate system -- or from the definition of the coordinates themselves -- you don't necessarily need to compare with Einstein-synced coords to detect anisotropy. For example, in the Leubner "everyday" sync (Reichenbach's [itex]\epsilon = 0[/itex]), the fact that light-speed is infinite in one direction is automatic by definition, and in other directions it cannot be infinite due to the experimental fact that 2-way (and n-way) speed of light is always isotropic.
Thanks for your answer. It is of big help to me. Would you accept the following way of stating:
The anisotropy is not a property of spacetime, but a property of the coordinate system conferred by the synchronization procedure. Different synchronization procedures confer different anisotropies. Observers of one inertial reference frame will never know the way in which the clocks are synchronized in the other one.
 
  • #30


bernhard.rothenstein said:
Thanks for your answer. It is of big help to me. Would you accept the following way of stating:
The anisotropy is not a property of spacetime, but a property of the coordinate system conferred by the synchronization procedure. Different synchronization procedures confer different anisotropies. Observers of one inertial reference frame will never know the way in which the clocks are synchronized in the other one.
Yes, except for the last sentence. Observers are not "in" one frame (everything is in every frame), and if clocks physically exist that have been synchronised in one frame, anyone can see that clock. In a theoretical context, though, the clocks may not physically exist, they are just notionally part of a thought experiment; "clock" is a convenient word to use as part of the process of assigning a time coordinate to an event. So, in that sense, yes, an observer may not know what time coordinate some other observer has decided to allocate to an event, unless she tells him what her synchronisation convention is.

I would also clarify that we are talking specifically about the anisotropy of the the 1-way speed of light, and not anisotropy in general.
 
  • #31
DrGreg said:
It's an unusual way to do things (mixing primed and unprimed coordinates) but, assuming the author makes no mistakes, there's nothing actually wrong with this and it could be of some practical use. A "moving" observer may be able to measure their distance on a "static" scale but only have access to their own "moving" clock, for example. (Of course, the words "static" and "moving" are both relative to a single inertial frame.) Dividing "static" distance by "moving" (i.e. proper) time you get something called "celerity" or "proper velocity" (see this post).



For the benefit of other readers I'll reproduce the abstract:

It was only a few years ago, soon after I started using this forum, that I realized that some of the standard relativistic effects, as described above, are coordinate-dependent and that other coordinate systems were permissible.

The point the authors are making is that there are lots of different coordinate systems to choose from apart from the standard "Einstein-synced" coordinates. Einstein coords are arguably the best coords but they are not the only coords, and it is educational to consider some of the other possibilities. The "everyday" coords that the authors define are one possibility.

The "radar coordinates" (e,r) which I defined in this post are another possibility. These are unusual because their two axes are not timelike and spacelike respectively, like most systems, but both null. (For mathematicians, radar coordinates are particularly interesting because they diagonalise the Lorentz transform; the two coord directions are eigenvectors and the k and k-1 red- and blue-shift Doppler factors are the eigenvalues.)

Time and space coordinates [tex](t(\epsilon), x)[/tex] can be defined from (e,r) by

[tex]t(\epsilon) = e + \epsilon(r - e) = (1 - \epsilon)e + \epsilon r[/tex]

[tex]x = c(r - e)/2[/tex]

(Sorry: you'll need to look closely at the above equations to see the difference between "epsilon" and "e".)

You have a choice of [tex]\epsilon[/tex]:

  • Standard Einstein-synced coordinates result when [tex]\epsilon[/tex] = ½. (t(E) in your notation.)
  • Leubner et al’s "everyday" coords result when [tex]\epsilon[/tex] = 0. (t(r) in your notation.)
  • Tangherlini coords (which I discussed in an earlier post in this thread) result when [tex]\epsilon[/tex] = ½(1 + v/c), where v is the supposed velocity of the observer relative to a postulated aether.

I think it is useful to be aware of these different coord systems, to help understand which relativistic effects are "intrinsic" (coord independent) – e.g. the twin "paradox" -- and which are not. However I’m not sure whether it’s a good idea to present all this to someone learning relativity for the first time; it might just confuse them.

I have a particular fondness for radar coordinates because of how, with k-calculus, they can be used to derive many results with quite simple proofs, and some without even having to define "simultaneity". The concept of "relative simultaneity" seems to be what most people have most difficulty understanding when learning relativity.

It is not clear to me whether Leubner’s "everyday" coords help with the original navigation problem. Nor am I convinced that using "base vectors" (I would call them "unit basis vectors") is the easiest method. I would think you just need to write down all the relevant equations to convert from one coord system to another and then it’s just maths (algebra) to solve them.

I’m not sure I’ve answered your question. Does any of this help you?
Consider please that I have performed the synchronization of the clocks of I using a signal that propagates in the positive direction of the OX axis with speed c(f)=c/n where n>1 represents a synchrony parameter. Please let me know how does n transform i.e. what is the relationship between n and n'.
 
  • #32
bernhard.rothenstein said:
Consider please that I have performed the synchronization of the clocks of I using a signal that propagates in the positive direction of the OX axis with speed c(f)=c/n where n>1 represents a synchrony parameter. Please let me know how does n transform i.e. what is the relationship between n and n'.
It depends exactly what you mean by n and n'. I'm hoping that you don't mean the refractive index of some medium (as it did in some other of your threads), but instead it means [itex]n=2\epsilon[/itex] in Reichenbach notation, or equivalently [itex]n=1-\lambda[/itex] in the Edwards notation I used in post #25 and earlier.

And I'm assuming that n' then refers to the equivalent concept according to some other inertial observer.

If that is the case, then the two inertial observers are free to choose whatever values of n and n' they wish; they are, in general, two independent parameters reflecting the two observers' choices of sychronisation. In a particular context, e.g. Selleri or Leubner or Einstein, there may be additional information that links two observers' choices together. But without such linkage, the two values are arbitary (and leading to the Edwards transform).
 

1. What is space-time transformation?

Space-time transformation is a mathematical concept used to describe the relationship between different frames of reference in space and time. It involves converting coordinates and measurements from one frame of reference to another.

2. How do space-time transformations with different shapes work?

Space-time transformations with different shapes involve using mathematical equations and formulas to map points and measurements from one frame of reference to another. The shape of the transformation determines the complexity and accuracy of the transformation.

3. What are the different shapes of space-time transformations?

There are various shapes of space-time transformations, including linear, quadratic, and exponential. Each shape represents a different level of complexity and accuracy in describing the relationship between frames of reference.

4. What is the importance of space-time transformations in physics?

Space-time transformations are crucial in physics as they allow us to understand and predict the behavior of objects in different frames of reference. They are essential in fields such as relativity, quantum mechanics, and cosmology.

5. How are space-time transformations with different shapes used in practical applications?

Space-time transformations with different shapes have practical applications in fields such as navigation, satellite communication, and GPS technology. They are also used in engineering and robotics to accurately map and navigate objects in space and time.

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