Maxwell's equations in relativistic case

In summary: Therefore, it can be concluded that both the differential and integral forms of Maxwell's equations hold in special relativity, with the difference being the speed at which the effects occur. In summary, the conversation discusses the relationship between Maxwell's equations in differential and integral form and how they apply in special relativity. The integral form states that in the case of an alternating magnetic field, the electric field will be induced with a delay of t=\frac {R} {c}, while the differential form does not account for this delay. However, this is not a paradox and can be explained by the Faraday's law of induction, showing that both forms of the equations hold in special relativity with the only difference being the speed at which the effects occur
  • #1
elivil
15
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It is often said that Maxwell's equations in differential form hold in special relativity while Maxwell's equations in integral form don't hold. Consider one of equations:
[tex]\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}} {\partial t}[/tex]
[tex] \oint_{\partial S} \mathbf{E} \cdot \mathrm{d}\mathbf{l} = - \frac {1} {c} \frac {d} {dt} \int \mathbf {B} \cdot \mathrm{d} \mathbf {S}[/tex]

Consider the integral form. It means that if one has an alternating magnetic field, then in any contour around this field circulation of electrical field immediately appears . If one takes a very long tube and at one end of the tube somehow generates an alternating magnetic field the in contour (radius R) around the tube circulation of electric field immediately appears. But in relativistic case it can't appear immediately because it will take time [itex]t=\frac {R} {c}[/itex] for news about alternating magnetic field to come to this contour. So here we have the violation of this equation in relativistic case.
Still this 'paradox' can be solved in terms of classical electrodynamics. But how?
 
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  • #2
The solution to this 'paradox' can be found in classical electrodynamics. According to the Faraday's law of induction, the electric field induced within the contour is proportional to the rate of change of the magnetic flux through the contour. So, in the case of an alternating magnetic field, the electric field will be induced with a delay of t=\frac {R} {c}. This means that the integral form of Maxwell's equations holds in special relativity, since the electric field will be induced with a delay of t=\frac {R} {c}, in accordance with the speed of light.
 
  • #3


I would respond by saying that the concept of time and simultaneity in special relativity is different from classical mechanics. In special relativity, the speed of light is constant and the laws of physics are the same in all inertial frames of reference. This means that the concept of "immediately" is not applicable in the same way as it is in classical mechanics.

In the example given, the circulation of electric field in the contour around the tube may not appear immediately, but this does not violate Maxwell's equations. The integral form of Maxwell's equations takes into account the time it takes for information to travel from one point to another.

Additionally, the concept of causality in special relativity also plays a role. In the example, the alternating magnetic field at one end of the tube is the cause for the circulation of electric field in the contour. However, in special relativity, causality is preserved, meaning that the cause must always precede the effect. This means that the circulation of electric field may not appear immediately, but it will still be caused by the alternating magnetic field.

In conclusion, the apparent violation of Maxwell's equations in the relativistic case can be explained by understanding the differences in the concept of time and causality in special relativity. Furthermore, the equations still hold true, but they must be interpreted differently in the relativistic context.
 

1. What are Maxwell's equations in the relativistic case?

Maxwell's equations are a set of four equations that describe the fundamental laws of electricity and magnetism. In the relativistic case, these equations are modified to take into account the effects of special relativity, such as time dilation and length contraction.

2. How do Maxwell's equations change in the relativistic case?

In the relativistic case, the equations are modified by the introduction of the Lorentz transformation, which accounts for the effects of special relativity. This leads to changes in the equations for electric and magnetic fields, as well as the introduction of new terms that describe the relationship between electric and magnetic fields.

3. What is the significance of Maxwell's equations in the relativistic case?

Maxwell's equations in the relativistic case are important because they provide a more complete and accurate description of the laws of electricity and magnetism. They also help to reconcile the discrepancies between classical mechanics and the principles of special relativity.

4. Can Maxwell's equations in the relativistic case be applied to all situations?

Maxwell's equations in the relativistic case are valid for all situations where the effects of special relativity are significant. This includes situations where particles are moving at high speeds, close to the speed of light, or in the presence of strong electric and magnetic fields.

5. How are Maxwell's equations in the relativistic case used in practical applications?

Maxwell's equations in the relativistic case are used in a variety of practical applications, including the design of electronic circuits, understanding the behavior of electromagnetic waves, and developing technologies like particle accelerators and MRI machines.

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