- #1
maniacp08
- 115
- 0
Heat/First Law of Thermodynamics/Calorimetry -- Have work done
A calorimeter of negligible mass contains 920 g of water at 303 K and 48 g of ice at 273 K. Find the final temperature T.
°C
Solve the same problem if the mass of ice is 460 g.
°C
Formula I've used
Mice * Lf + Mice * Cwater * change in T icewater = Mwater * Cwater * change in T water
(.048kg)(79.7kcal/kg)+(.048kg)(1kcal/kgxK)(Tf - 273K) =
(.92kg)(1kcal/kgxK)(303K-Tf)
Ive gotten Tf to be 297.56K which is 24.41 C
and for part B I've gotten the answer to be 266.433K which is -6.7167 C
Is this correct?
A calorimeter of negligible mass contains 920 g of water at 303 K and 48 g of ice at 273 K. Find the final temperature T.
°C
Solve the same problem if the mass of ice is 460 g.
°C
Formula I've used
Mice * Lf + Mice * Cwater * change in T icewater = Mwater * Cwater * change in T water
(.048kg)(79.7kcal/kg)+(.048kg)(1kcal/kgxK)(Tf - 273K) =
(.92kg)(1kcal/kgxK)(303K-Tf)
Ive gotten Tf to be 297.56K which is 24.41 C
and for part B I've gotten the answer to be 266.433K which is -6.7167 C
Is this correct?