Three spring two mass system, compression of the middle spring

In summary, the effective mass is the mass of the spring after it's been distorted by the forces acting on it.
  • #1
Leb
94
0
Homework Statement

I decided to revise my mechanics course and came across a problem involving a system with three springs (say, different k's) and two masses (say different).
The s1-m1-s2-m2-s3 system has the outer springs connected to walls of infinite mass.

I was interested in what happens to the system (i.e. in terms of forces) if we were to pull the masses in opposite directions by displacement [itex]x_{1}[/itex] and [itex]x_{2}[/itex] respectively ([itex]x_{1}[/itex] is to the -ve dirrection) ?

The attempt at a solution

[itex] F_{1,1}=k_{1}.x_{1}[/itex]
since the spring needs to return to the equilibrium position which is to the right.
[itex]F_{2,1}=k_{2}.(x_{1}+x_{2})[/itex]
since the spring needs to return to the equilibrium position which is to the right. (Spring is streched by x1+x2)
[itex]F_{2,2}=-k_{2}.(x_{1}+x_{2})[/itex]
since the spring needs to return to the equilibrium position which is to the right.
[itex]F_{3,2}=-k_{3}.x_{2}[/itex]
since the spring needs to return to the equilibrium position which is to the left.

Combining all of this I get the following:
[itex]m_{1} \ddot{x_{1}} =F_{1,1}+F_{2,1}=k_{1}.x_{1}+k_{2}(x_{1}+x_{2}) [/itex]
[itex]m_{2} \ddot{x_{2}} =F_{2,2}+F_{3,2}=-k_{2}(x_{1}+x_{2})-k_{3}.x_{2}[/itex]

Does this seem correct ?
I was trying to compare this with the usual example, where masses are moved to one direction (which stated, that the middle spring can be either expanded OR compressed, and I would get the same, if I were to replace the value of [itex]x_{1}[/itex] to its negative. However, this would imply that the length of spring 2 actually decreases (instead of increasing), so, is their generalization (i.e. works for both compressed and expanded spring) wrong or is there something I do not get ?

Thank you for your time.
 
Last edited:
Physics news on Phys.org
  • #2
Looks like you have a mixed sign convention with x1 positive right and x2, e.g. Changing the initial displacements won't change the equations of motions as long as the sign convention is the same.
 
  • #3
Thank you for the reply !

I am confused with one more thing, the concept of tension in a spring. I do not really understand how it works in a spring, when it is not supported by one side.

a) Should I consider the spring not to move if its center is not moving ?

b) Could someone please explain me the following situations ?

1) Compress a spring on both sides, and release both sides simultaneously.

Will FOn End Of Spring by Restoring Force on both sides(force pointing away from the center of the spring) will be 'coupled' with a Tension which would point towards the center of the spring, with a magnitude that increases as the spring expands until some point (to stop the spring from expanding infinitely) ?

2) Stretch a spring on both sides and release both sides simultaneously.

Will the restoring force (pointing towards the center) be 'coupled' with tension pointing from the center (again with increasing magnitude until some point)

3) I think what I really do not understand is how to view forces in a spring.
For instance in the image below, it states that after some perturbation of the masses to the right, the spring in the middle will have tension pointing towards the center...

OK, so for m1 to move to the right it is clear that we need a force acting on the mass to the right to be greater than on the left. However, I do not get, why the tension is pointing to the center in in the middle spring ( since the spring is compressed from the left and expanded from the right, how can we say, that the center of the spring did not move ?)

http://img535.imageshack.us/img535/8139/massspring.jpg
 
Last edited by a moderator:
  • #5


I would say that your solution seems correct based on the information provided. However, I cannot fully confirm its accuracy without further information about the specific values of the masses and spring constants.

Regarding your question about the middle spring being compressed or expanded, the generalization you mentioned may be misleading. The behavior of the spring depends on the direction and magnitude of the forces applied to it. In this case, the forces applied to the middle spring are in opposite directions, resulting in a net force of zero and no change in its length. It is important to consider all the forces acting on the system to accurately analyze its behavior.
 

What is a three spring two mass system?

A three spring two mass system refers to a physical system consisting of two masses connected by three springs, with one of the springs located in the middle.

How does the compression of the middle spring affect the system?

The compression of the middle spring affects the system by altering the equilibrium position and the natural frequency of the system. It also affects the distribution of forces and energy within the system.

What is the equilibrium position of a three spring two mass system?

The equilibrium position of a three spring two mass system is the point at which the system is in a state of balance, with no net force acting on either mass. This occurs when all three springs are at their natural lengths.

How does the stiffness of the middle spring impact the system?

The stiffness of the middle spring can significantly impact the behavior of the system. A stiffer middle spring will result in a higher natural frequency and a smaller compression of the middle spring for a given force. It can also affect the stability of the system.

What are some real-world applications of a three spring two mass system?

A three spring two mass system can be found in various mechanical systems, such as car suspensions, shock absorbers, and even in structures like buildings and bridges. It is also commonly used in research and experimentation to study the dynamics of a multi-spring system.

Similar threads

  • Introductory Physics Homework Help
Replies
18
Views
259
  • Introductory Physics Homework Help
2
Replies
40
Views
2K
  • Introductory Physics Homework Help
Replies
24
Views
1K
  • Introductory Physics Homework Help
Replies
15
Views
251
  • Introductory Physics Homework Help
Replies
8
Views
324
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
18
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
442
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
31
Views
1K
Back
Top