- #1
yourmom98
- 42
- 0
Given {x | -50 < x < 50}, {y | 0 < y < 20} vertex at (0,20) it is a parabola find the equation in (x-h)^2=4p(y-k)
its pretty easy except how do i find p?
its pretty easy except how do i find p?
The equation for a parabola in standard form is y = ax^2 + bx + c, where a represents the coefficient of the squared term, b represents the coefficient of the linear term, and c represents the constant term. In this case, the equation would be y = ax^2 + bx + c with the given values for x and y.
The value of p can be found by solving for x in the equation y = ax^2 + bx + c. Once x is found, p can be determined by substituting the value of x into the given range of values for x.
The given range of values for x and y represents the domain and range of the parabola. This means that any point within this range can be plotted on the graph of the parabola. The range of values for x also helps to determine the value of p in the parabola.
This parabola differs from a regular parabola in that it has a limited range of values for both x and y. This means that the parabola is only defined within a specific area, rather than extending infinitely in both directions. It also means that the vertex of the parabola may not be at the origin, as it would be in a regular parabola.
Yes, there are other methods that can be used to find the value of p in this parabola, such as using the quadratic formula or graphing the parabola and finding the x-intercepts. However, the given range of values for x and y can provide a quick and easy way to determine the value of p.