Need Help With Series-Parallel Ohms Law Circuit Math Problem

In summary: If all Resistors in a Parallel circuit are equal size, then the Current through each is Equal? True or False?False, because the current through resistor 1 will be greater then the current through resistor 2, and resistor 3 will have less current then both of the others.
  • #1
ChainedBoxer
12
0

Homework Statement



Total Volts: 10
Resistor 1 - R1: 1K
Resistor 2 - R2: 4K
Resistor 3 - R3: 4K

Photo That I Made Of The Series-Parallel Circuit:
http://imageshack.us/photo/my-images/266/circuitn.png/



Homework Equations



http://en.wikipedia.org/wiki/Series_and_parallel_circuits

The Attempt at a Solution



Total Current: 0.5
Voltage Across R1: 0.167
Current Through R3 In Amps: 0.5
Current Through R2: 0.333
Total Circuit Power In Watts: 3
Power Consumed By R3 In Watts: 1.5
 
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  • #2
How'd you come up with those answers?
 
  • #3
vela said:
How'd you come up with those answers?

I came up with them based on the formulas that I read, but I know they must be wrong because they are not adding up to what the numbers should be based on the multiple choice questions that I was given.

((NOTE: Where the question "What Is the Current Through R1 In Amps?", it should read "R2" instead.))

Known Circuit Values:

Total Voltage: 10 Volts
Resistor 1 - R1 - In Series - Value: 1K
Resistor 2 - R2 - In Parallel With R3 - Value: 4K
Resistor 3 - R3 - In Parallel With R2 - Value: 4K

Questions:

1. What Is The Total Current Equal to In Amps?

2. What Is The Voltage Across R1?

3. What Is The Current Through R3 In Amps?

4. What Is The Current Through R2 In Amps? (I First Listed It As R1 In The Pic, But It Should Be R2).

5. What Is The Current Value Through R1 In Watts?

6. What Is The Total Power Consumed In Watts?

7. What Is The Power Consumed By R3 In WattsCan anyone help me out here?
 
  • #4
How are you going about determining this:

1. What Is The Total Current Equal to In Amps?
 
  • #5
We want to see your actual calculations so we can see where you are going wrong.
 
  • #6
NascentOxygen said:
How are you going about determining this:

1. What Is The Total Current Equal to In Amps?


Are you referring to question 5 "5. What Is The Current Value Through R1 In Watts?"? That should be Amps. My mistake.

And I will see if I can post some of my notes here, to help you figure out what I am doing wrong. I have a bunch of them, but I don't know if I can write them in a way to actually explain what steps that I have been taking so far.
 
  • #7
Start at the beginning. I'd like to see how you determine the current flowing from the 10v source.
 
  • #8
NascentOxygen said:
Start at the beginning. I'd like to see how you determine the current flowing from the 10v source.



For the 10 Volts and Current, I created a chart based on what I found on a site dealing with this type of math. I can't create the chart in the thread, but I can try and list some of the math problems that I used. Since all Voltage is equal in a parallel circuit, the top of the chart had 10 Volts listed as all of the answers. The Amps came out to, R1-10, R2-2.5, R3-2.5, for a total of 15. The Resistance on the chart had the Resistance as R1-1, R2-4, R3-4, for a total of 0.666. I know the chart came out to be wrong, because the answers didnt match any of the choices. Can you tell me what I did wrong? This chart worked on all of my Series math problems, but the version for Parallel didn't match up.
 
  • #9
There is one other problem that I have been having problems with. Its a True or False question. Can anyone here help me find the answer?

If all Resistors in a Parallel circuit are equal size, then the Current through each is Equal? True or False?
 
  • #10
ChainedBoxer said:
If all Resistors in a Parallel circuit are equal size, then the Current through each is Equal? True or False?
That's true, and is a fact that you can use when considering the two 4kΩ
resistors in your circuit.
 
  • #11
Do you know Ohm's Law? Can you answer questions such as: if a 100 ohm resistor has 0.5 amps flowing through it, what reading would a voltmeter give if you connected it across the two terminals of that resistor?
 
  • #12
NascentOxygen said:
That's true, and is a fact that you can use when considering the two 4kΩ
resistors in your circuit.

Thanks! That is what I originally had as the answer, but I wasn't sure. The book mention something to this effect, but it was written in a way where I couldn't tell if True was correct.

How would I use this to help me solve the two 4K resistors? And the "K" means 1000 right? So its actually 4000 or .1000?
 
  • #13
NascentOxygen said:
Do you know Ohm's Law? Can you answer questions such as: if a 100 ohm resistor has 0.5 amps flowing through it, what reading would a voltmeter give if you connected it across the two terminals of that resistor?


Yeah I know Ohms Law, but I am having a problem figuring out Series-Parallel math. I x V = 50 Volts. At least I think that is right.
 
  • #14
ChainedBoxer said:
And the "K" means 1000 right?
Yes. I prefer a lower-case "k" for 1000.

So its actually 4000 or .1000?
I'm not sure what "it" is that you refer to. But I'm puzzled by that decimal point.
 
  • #15
NascentOxygen said:
Yes. I prefer a lower-case "k" for 1000.


I'm not sure what "it" is that you refer to. But I'm puzzled by that decimal point.

I don't know what it your referring to. And I haven't been doing this type of math for very long and I am 10+ years out from high school; so I don't remember everything from that time math wise. So I wasnt sure if K in this type of math meant 1000, or it meant something else.

So have I posted enough to where you can start helping me figure out this math? Like tell me which formulas to use for each question?
 
  • #16
The "formula" for any number of resistors in parallel is easiest remembered as:

1/R = 1/R1 + 1/R2 + 1/R3 + ...

So work out the sum of the reciprocals, then take the reciprocal of that.

For 2 resistors in parallel, this boils down to:
R = (product of the resistances) / (sum of the resistances)

Does that help?
 
  • #17
NascentOxygen said:
The "formula" for any number of resistors in parallel is easiest remembered as:

1/R = 1/R1 + 1/R2 + 1/R3 + ...

So work out the sum of the reciprocals, then take the reciprocal of that.

For 2 resistors in parallel, this boils down to:
R = (product of the resistances) / (sum of the resistances)

Does that help?

How do I figure out the resistor that is in Series, with the two from Parallel? You said to use the formula for the two resistors in parallel, but there is also a resistor in Series. How do I add them all up?
How do I find the Total Current? The Voltage Drop over R1? The current through R1, R2 and R3? Find Total Watts? The Watts consumed by R3?
 
  • #18
Once you have worked out the resistance of the 2 in parallel, you can then treat that pair as a single resistance. It is in series with R1, so you add your answer to the resistance of R1 to arrive at the total circuit resistance. For resistances in series, their values simply add together.
 
Last edited:
  • #19
NascentOxygen said:
Once you have worked out the resistance of the 2 in parallel, you can then treat that pair as a single resistance. It is in series with R1, so you add your answer to the resistance of R1 to arrive at the total circuit resistance. For resistances in series, their values simply add together.



Thanks for your help so far! I'm learning a good amount of things from this thread. Last night and into the morning I have been trying to better figure out these questions and I came up with some possible answers. Can you please tell me if I got any of them wrong and I will do them over again until I get them right.


2. What Is The Voltage Across R1? (I Came Up With C Being The Right Answer.)
A - 0.5
B - 2
C - 0.0033
D - 3

3. What Is The Current Through R3 In Amps? (I Came Up With B Being the Right Answer.)
A - 2
B - 3.3
C - 6
D - 1.5

4. Total Current Through R2 In Amps (I Came Up With A Being The Right Answer).
A - .00165
B - 0.5
C - 0.333
D - 0.167

5. What Is The Current Value Through R1 In Amps? (I Came Up With D Being The Right Answer)
A - 2
B - 3.3
C - 0.333
D - 0.167

6. What Is The Total Power Consumed In Watts? (I Came Up With C Being The Right Answer)
A - 1.5
B - 3
C - 0.333
D - 0.167

7. What Is The Power Consumed By R3 In Watts? (I Came Up With C Being The Right Answer)
A - 0.5
B - 1.5
C - .01089
D - 5
 
  • #20
Also, how do I convert circuit values like this "6,67.0,00166= 0,0011W"? I know how to convert numbers like 60/1000, but not the one with commas in them.
 

1. What is Ohm's Law?

Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them.

2. What is a series circuit?

A series circuit is a circuit in which the components are connected end to end, one after the other. The same current flows through each component in a series circuit.

3. What is a parallel circuit?

A parallel circuit is a circuit in which the components are connected in branches, with each component having its own separate path for current to flow. The voltage across each component in a parallel circuit is the same.

4. How do I solve a series-parallel circuit math problem?

To solve a series-parallel circuit math problem, you will need to use a combination of Ohm's Law and Kirchhoff's Laws. First, calculate the total resistance of the circuit by adding up the resistances in the series portion and using the reciprocal formula for resistors in parallel. Then, use Ohm's Law to calculate the current in the circuit. Finally, use Kirchhoff's Laws to determine the voltage drops and current in each individual branch of the circuit.

5. Can you provide an example of a series-parallel circuit problem and how to solve it?

Yes, for example, consider a circuit with three resistors: R1 = 10 ohms, R2 = 20 ohms, and R3 = 30 ohms. R1 and R2 are in series, and R3 is in parallel to the combination of R1 and R2. The voltage source is 12 volts. To solve this, first calculate the total resistance: R1 + R2 = 10 + 20 = 30 ohms. Then, find the reciprocal of this value: 1/30. Add this value to the reciprocal of R3: 1/30 + 1/30 = 2/30. Take the reciprocal again to get the total resistance of the circuit: 30/2 = 15 ohms. Next, use Ohm's Law to calculate the current: I = V/R = 12/15 = 0.8 amps. Finally, use Kirchhoff's Laws to determine the voltage drops and current in each branch. The voltage drop across R1 and R2 will be 0.8 amps * 10 ohms = 8 volts. The voltage drop across R3 will be 0.8 amps * 30 ohms = 24 volts. The current through R1 and R2 will be 0.8 amps, and the current through R3 will be 0.8 amps * (30 ohms / 15 ohms) = 1.6 amps.

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