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madmike159
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How would i rearange [itex]A=2\pi r(r+h)[/itex] to make h the subject?
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madmike159 said:How would i rearange A=2[tex]\pi[/tex]r(r+h) to make h the subject?
To make h the subject of this formula, we need to isolate it on one side of the equation. We can do this by first distributing 2 pi r to get A=2 pi r^2 + 2 pi r h. Then, we can subtract 2 pi r^2 from both sides to get A-2 pi r^2=2 pi r h. Finally, we can divide both sides by 2 pi r to get h=(A-2 pi r^2)/(2 pi r).
Rearranging the formula allows us to express h in terms of the other variables in the equation. This can be useful in solving problems or finding the value of h when the other variables are known.
The constant 2 pi represents the circumference of a circle, which is necessary when calculating the surface area of a cylinder. It is a mathematical constant that is often used in geometric formulas.
Yes, we can rearrange the formula to make r or A the subject by using similar algebraic methods. For example, to make r the subject, we can divide both sides by 2 pi(r+h) to get r=A/(2 pi(r+h)).
This formula is often used in various engineering fields, such as construction, architecture, and manufacturing. It is used to calculate the surface area of cylinders, which can be found in structures like pipes, tanks, and engines. It is also used in physics and astronomy to calculate the volume and surface area of celestial bodies that have a cylindrical shape, such as certain planets and moons.