Electric Field inside and outside of Dielectric sphere

In summary, the conversation discusses the determination of the electric field inside and outside a dielectric sphere with uniform permanent polarisation. The conversation suggests using the Laplace's equation and considering two separate potentials for inside and outside the sphere, with the equation D = ε0E0 + P used to match boundary conditions. The purpose of this equation is to solve the problem by finding the coefficients Al and Bl.
  • #1
JayKo
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Homework Statement



A dielectric sphere of radius R has a uniform permanent polarisation P. Determine the electric field both inside and outside the sphere. (Hint: Since div P = 0 everywhere, the electrostatic potential satisfies Laplace's equation. Do not assume that the sphere is characterised by a dielectric constant. Instead, use D = [tex]\epsilon_{0}[/tex]E0 + P.)

Homework Equations



use the laplace equation where the general form of potential is:
[tex]V=\Sigma (A_{l}r^{l}P_{l}(cos(theta))+B_{l}*1/(r_{l+1})*P_{l}(cos(theta)))[/tex]

The Attempt at a Solution



set the boundary condition when outside of sphere :
r ->infinity, V->0 hence Al=0

when inside the sphere
r-> 0, V not= infinity hence Bl=0

the next time is to find both the coefficients, a.k.a Al and Bl. so far am i heading the right directions?my question is also what D = [tex]\epsilon_{0}[/tex]E0 + P purpose here in solving this problem?
 
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  • #2
There are two regions in space, one inside and one outside the sphere. Therefore, you need to consider two separate potentials, one inside and one outside, then match boundary conditions. That's where the equation ##\mathbf{D}=\epsilon_0 \mathbf{E}+\mathbf{P}## comes in.
 

1. What is an electric field?

An electric field is a physical quantity that describes the force experienced by a charged particle within a given space. It is represented by a vector and its magnitude and direction determine the force on the charged particle.

2. What is a dielectric sphere?

A dielectric sphere is a spherical object made of a material that does not conduct electricity easily, known as a dielectric material. Examples of dielectric materials include rubber, glass, and plastic.

3. How is the electric field affected by a dielectric sphere?

The presence of a dielectric sphere in an electric field can alter the electric field lines, causing them to bend and concentrate more in the surrounding space. This results in a decrease in the overall strength of the electric field.

4. What happens to the electric field inside and outside of a dielectric sphere?

Inside the dielectric sphere, the electric field is weaker compared to the outside, as the charged particles in the dielectric material create an opposing electric field. Outside the sphere, the electric field is slightly stronger due to the concentration of the field lines around the surface of the sphere.

5. How can the electric field inside and outside of a dielectric sphere be calculated?

The electric field inside and outside of a dielectric sphere can be calculated using the Coulomb's law and the concept of electric displacement. The electric field inside the sphere is given by E = (1/4πε) * (Q/R^3) * r, where ε is the permittivity of the dielectric material, Q is the charge of the sphere, R is the radius of the sphere, and r is the distance from the center of the sphere. The electric field outside the sphere is given by E = (1/4πε) * (Q/R^2).

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