- #1
jmc8197
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The following comes from Landau's Mechanics, pages 97 - 98.
For a particle in a rigid body, v = V + W x r -- (1)
where for some origin O of the moving body measured in the "fixed" system of
co-ordinates, v = particle's velocity in body in the "fixed" system, V = velocity of O in "fixed" system , W is the body's angular velocity in *fixed system", x is a cross product and r the particle's radial vector within body measured from O.
For another origin, O' distance a from O, r = r' + a, and substituting in
(1) gives:
v = V + W x a + W x r'. The definition of V' and W' shows that v = V' + W' x
r' and so
V' = V + W x a, W' = W -- (2)
He then says that the first part of (2) shows that if V and W are
perpendicular for a choice of origin O, then V' and W' are also
perpendicular for O'. Why?
Thanks in advance.
For a particle in a rigid body, v = V + W x r -- (1)
where for some origin O of the moving body measured in the "fixed" system of
co-ordinates, v = particle's velocity in body in the "fixed" system, V = velocity of O in "fixed" system , W is the body's angular velocity in *fixed system", x is a cross product and r the particle's radial vector within body measured from O.
For another origin, O' distance a from O, r = r' + a, and substituting in
(1) gives:
v = V + W x a + W x r'. The definition of V' and W' shows that v = V' + W' x
r' and so
V' = V + W x a, W' = W -- (2)
He then says that the first part of (2) shows that if V and W are
perpendicular for a choice of origin O, then V' and W' are also
perpendicular for O'. Why?
Thanks in advance.