Calculus - find dy/dt thank you

[laker_gurl3]

calculus -.. find dy/dt...thank you..:(

can someone please help me out with this question...i did it all sorts of way,quotient rule, product rule..etc.. but i can never match the answer in the book..i just want to know if u did..

find dy/dt = x^2 Tanx / sec x

The answer in the book was
x(xcosx + 2sinx)

lemmi know how you did it with a couple steps! thanks soo mcuh

 

[Data]

Do you mean find

$$\frac{d}{dx} \frac{x^2 \tan{x}}{\sec{x}}$$

?

If so, here:

$$\frac{x^2 \tan{x}}{\sec{x}} = x^2\tan{x}\cos{x} = x^2 \frac{\sin{x}}{\cos{x}}\cos{x} = x^2 \sin{x}$$

I'm sure you can take the derivative from there~

 

[Nylex]

Damn you Data!

 

[Data]

got to be quick :tongue: