Average force of a steel ball

In summary, the problem involves a 3.00 kg steel ball bouncing off a wall with a speed of 9.0 m/s at an angle of 60°. The ball is in contact with the wall for 0.200 s and the question asks for the average force exerted by the wall on the ball. To solve this, we use the equation ΣFavg=ΔP/Δt and find the x and y components of the initial and final velocities to plug into the equation. The final answer for the average force is -135 N.
  • #1
chocolatelover
239
0

Homework Statement


A 3.00 kg stell ball strikes a wall with a speed of 9.0m/s at an angle of 60° with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for .200 s, what is the average force exerted by the wall on the ball?


Homework Equations


ΣFavg=1/Δt integral ΣFdt from ti to tf



The Attempt at a Solution



F avg=1/.200(3.00kg)(9.8m/s^2)x|0 to .200
=29.4N

Could someone please tell me if this looks correct and if now could someone please show me where I went wrong?

Thank you very much
 
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  • #2
chocolatelover said:

The Attempt at a Solution



F avg=1/.200(3.00kg)(9.8m/s^2)x|0 to .200
=29.4N

The force you use here is the force of gravity, which isn't what the question is asking. The question is asking for the average force of the water on ball. You don't need to worry about gravity for this problem, because it is merely an impulse problem. Remember:
[tex]\int F dt=\Delta P[/tex]
 
  • #3
Thank you very much

Does this look right?

integral from 1.25 to .800 (.110kg)(9.8m/s^2)dt

=.8624-1.35
=-.4876

Thank you
 
  • #4
Edit:

Does this look right?

integral 3.00(9.8)dt from 0 to .200=
3.00kg(9.8m/s^2)x=
3.00(9.8)(.200)=
5.88

Thank you very much
 
  • #5
Hi chocolatelover,

I think you misunderstood Nabeshin's post. We are searching for the force, we don't know what it is. (When you set the force as 3 kg * 9.8 m/s^2, that is the force of gravity on the ball; but you want the force from the wall.)

If they are looking for the average force, the integral form reduces to

[tex]
\vec F_{\rm avg}(\Delta t)= \Delta \vec p
[/tex]

How do you find [itex]\vec F_{\rm avg}[/itex]? Can you evaluate the other parts of the equation?
 
  • #6
Does this look right?

Favg(.200s)=3.0kg(9.0)
Favg=-135N

Thank you
 
  • #7
chocolatelover said:
Does this look right?

Favg(.200s)=3.0kg(9.0)
Favg=-135N

Thank you

You need to take into account the vector nature of the formula. In the x direction, and for a one object system, the formula is:

[tex]
F_{{\rm avg},x} (\Delta t)= m v_{f,x} - m v_{i,x}
[/tex]

and a similar equation for y.

To evaluate this, you'll need to find the x and y components of the initial and final velocities, and plug them into the x equation and the y equation.
 
  • #8
Thank you very much

Regards
 

1. What is the definition of average force of a steel ball?

The average force of a steel ball is the amount of force that is exerted on an object over a certain period of time, typically measured in Newtons (N).

2. How is the average force of a steel ball calculated?

The average force of a steel ball can be calculated by dividing the change in momentum of the ball by the time it takes for that change to occur. This can be represented by the equation F = Δp/Δt, where F is the average force, Δp is the change in momentum, and Δt is the time interval.

3. How does the mass of the steel ball affect the average force?

The mass of the steel ball does not directly affect the average force, but it does affect the momentum and therefore can indirectly affect the average force. A heavier steel ball will have a greater momentum and therefore may require a larger force to change its direction or speed.

4. What factors can influence the average force of a steel ball?

There are several factors that can influence the average force of a steel ball, including its mass, speed, and the surface it is rolling or colliding on. Other factors such as air resistance and friction can also play a role in the average force.

5. How is the average force of a steel ball used in real-world applications?

The average force of a steel ball is used in various real-world applications, such as in sports like bowling or billiards where the force of impact between the ball and other objects needs to be calculated. It is also used in engineering and physics experiments to understand the motion and behavior of objects under the influence of force.

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