- #1
RadiationX
- 256
- 0
I think that I'm over looking something with this problem. Below is the equation of an hyperbola in polar form.
[tex]R=\frac{1}{1 + 2cos{\theta}}[/tex]
when [tex]\theta =\pi[/tex] shouldn't [tex]R = -1[/tex]? And not [tex]R= 1[/tex]
Am I over looking some property of the [tex]\cos[/tex] function?
Even when i evalute this expression at [tex]\theta=\pi[/tex]in my ti-89 i get that R is = to 1. What am i not seeing?
[tex]R=\frac{1}{1 + 2cos{\theta}}[/tex]
when [tex]\theta =\pi[/tex] shouldn't [tex]R = -1[/tex]? And not [tex]R= 1[/tex]
Am I over looking some property of the [tex]\cos[/tex] function?
Even when i evalute this expression at [tex]\theta=\pi[/tex]in my ti-89 i get that R is = to 1. What am i not seeing?