Energy of Orbiting Satellites

In summary, the problem involves calculating the change in gravitational potential energy of a 6200kg satellite that lifts off from Earth's surface into a circular orbit of altitude 2500km. The calculation involves using the formula Eg = -GMm/r and determining the change in Eg, which is -1.265577793 x10^11J. Another problem involves calculating the height a rocket would reach when launched vertically from Earth's surface with a velocity of 3.4km/s. For this problem, the formula used is r = 2GM/V^2, which results in a height of 7.0x10^7m from Earth's center. To calculate the height from Earth's surface, the radius of the Earth
  • #1
six789
127
0
this is the problem...
What is the change in gravitational potential energy of a 6200kg satellite that lifts off from Earth's surface into a circular orbit of altitude2500km?

i did this...
r = rE +h
=6.38 x10^6m + 2.5 x10^6m
r=8.88 x10^6m

Eg= -GMm
r
=-6.673x10-11N m2/kg2 (5.98 x10^24kg)(6200kg)
8.88 x10^6m
Eg=-2.786127793 x10^11J

Eg=mgh
=6200kg(9.82m/s2)(-2.5 x10^6m)
Eg=-1.52055 x10^11J

Change in Gravitational Potential Energy
∆ Eg = Eg - Eg
=-2.786127793 x10^11J – (-1.52055 x10^11J)
∆ Eg =-1.265577793 x10^11J

but the answer on my book is 1.1x10^11J, can anyone check this, coz I am not sure where is the mistake.. thanks for the help
 
Last edited:
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  • #2
Your problem is here:

Eg=mgh
=6200kg(9.82m/s2)(-2.5 x10^6m)
Eg=-1.52055 x10^11J

You should have just the used the same form used in the prior Eg formula

[tex]E_g = \frac{GMm}{R}[/tex]

with a different value for R
 
  • #3
satellites

thanks for the help... i get the answer now...
 
  • #4
another problem is... a rocket is launched vertically from Earth's surface with a velocity of3.4km/s. How high it go a)from Earth's centre and b) from Earth's surface.
a)r = 2GM
V^2
= 2(6.673x10^-11N m^2/kg^2) (5.98 x10^24kg)
(3400m/s)^2
r=7.0x107m

i don't know waht to do with b), i am thinking to add the raduis of the earth, but my answer is wrong... the answer should be 650km.
 
Last edited:

1. What is the energy source for orbiting satellites?

The energy source for orbiting satellites is typically a combination of solar energy and chemical energy from rocket propellants used to launch the satellite into orbit.

2. How does the energy of a satellite affect its orbit?

The energy of a satellite determines its orbit by influencing its speed and distance from the Earth. A satellite with more energy will have a higher speed and a larger orbit, while a satellite with less energy will have a slower speed and a smaller orbit.

3. How is the energy of a satellite calculated?

The energy of a satellite is calculated using the formula E = -GmM/2r, where G is the gravitational constant, m is the mass of the satellite, M is the mass of the Earth, and r is the distance between the satellite and the center of the Earth. This formula takes into account both the gravitational potential energy and the kinetic energy of the satellite.

4. Can a satellite run out of energy?

Yes, a satellite can run out of energy if it is not periodically boosted or refueled. This is because satellites experience atmospheric drag and gravitational forces that can slow them down over time, causing their orbits to decay. To prevent this, satellites may use small engines or thrusters to maintain their orbit.

5. How is energy used by satellites for communication and other functions?

Satellites use energy for various functions, including communication, data collection, and maintaining their position in orbit. This energy is typically generated by solar panels that convert sunlight into electricity. This electricity is then stored in batteries or used to power the satellite's systems directly.

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