- #1
Niles
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I have E(v) = (mc^2)/(sqrt(1-(v^2/c^2)).
I have found the second-order Taylor-polynomial for v=0, and I get:
T_2_E(v) = mc^2 + ½mv^2.
My teacher asks me, why this equation must be true - what is so special about the second order Taylor-polynomial for v = 0 for E(v)?
I have found the second-order Taylor-polynomial for v=0, and I get:
T_2_E(v) = mc^2 + ½mv^2.
My teacher asks me, why this equation must be true - what is so special about the second order Taylor-polynomial for v = 0 for E(v)?
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