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tarekkkkk
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Modern physics special relativity
Two spaceships,A and B move toward each other on a head-on collision course,According to an observer at rest,both spaceships have a velocity of 0.6c along the x-axis.At the time of observation(t=0),spaceship A has the same x value (x=0) as the observer,and spaceship B is at a distance of 100 km away from him.
At what time will the collision occur for the observer at rest and for an observer on spaceship A?
my thought ok don't laugh... T=(2L/c)/((1-v/c)/(1+v/c))^(1/2) for the spaceship A
and T=(2L/c)/(1-v^2/c^2)^(!/2) for the observer at rest and L= 50 km when the collision happen thanks in advance
Homework Statement
Two spaceships,A and B move toward each other on a head-on collision course,According to an observer at rest,both spaceships have a velocity of 0.6c along the x-axis.At the time of observation(t=0),spaceship A has the same x value (x=0) as the observer,and spaceship B is at a distance of 100 km away from him.
At what time will the collision occur for the observer at rest and for an observer on spaceship A?
Homework Equations
my thought ok don't laugh... T=(2L/c)/((1-v/c)/(1+v/c))^(1/2) for the spaceship A
and T=(2L/c)/(1-v^2/c^2)^(!/2) for the observer at rest and L= 50 km when the collision happen thanks in advance
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