Mechanics - Orbits under Central Force

In summary, the conversation discusses the motion of a particle in a plane attracted by a fixed point with a force of zr^-5. The orbit is determined to be r=acos(theta) by using the orbit equation and substituting u=1/(a*cos(theta)). The conversation also addresses a discrepancy in the equation and suggests substituting the value of u to test the solution.
  • #1
Master J
226
0

Homework Statement


A particle moving in a plane is attracted towards a point (fixed) by a force zr^-5. The particle is projected from an apse at distance a with speed SQRT(z/(2a^4)).

Show that the orbit is r=acos(theta)

Using the Orbit Eq: d^2 u/dC^2 + u = za^-5/(hu)^2

h = angular momentum, or r(speed) in this case, u = 1/r



I get down to (du/dC)^2 + u^2 = -4/[(a^3)u] + A

where C = theta, A = integration constant.

Am I correct so far?
 
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  • #2
za^-5/(hu)^2 should be zu^5/(hu)^2 shouldn't it? Rather than solving the equation, why don't you just substitute u=1/(a*cos(theta)) and see if the solution works?
 
  • #3
Why is that?
 
  • #4
Because if the radial force per unit mass is z/r^5 and r=1/u that turns into zu^5.
 

1. What is a central force in mechanics?

A central force is a type of force that acts on an object towards or away from a fixed point, called the center of force. This force is always directed along the line connecting the object to the center of force.

2. What are the types of orbits under central force?

The three types of orbits under central force are circular, elliptical, and parabolic. A circular orbit is when the object moves in a circular path around the center of force, while an elliptical orbit is an oval-shaped path. A parabolic orbit is a path that is neither circular nor elliptical, but rather a straight line that intersects the center of force.

3. How is the motion of an object under central force described?

The motion of an object under central force is described by Kepler's laws of planetary motion. These laws state that the object follows an elliptical orbit, with the center of force at one focus of the ellipse. The object also sweeps out equal areas in equal times and the square of the orbital period is directly proportional to the cube of the semi-major axis of the ellipse.

4. What is the equation for calculating the centripetal force in an orbit under central force?

The equation for calculating the centripetal force in an orbit under central force is F = (m * v^2) / r, where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the distance between the object and the center of force.

5. How does the central force affect the trajectory of an object?

The central force affects the trajectory of an object by determining the shape and size of the orbit. A stronger central force will result in a smaller orbit, while a weaker central force will result in a larger orbit. The direction of the force also affects the trajectory, as it determines whether the orbit is clockwise or counterclockwise.

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