- #1
Freyth
- 12
- 2
Question on Motion of a car round a banked track [SOLVED]
A racing car of 1000kg moves round a banked track at a constant speed of 108km/h. Assuming the total reaction at the wheel is normal to the track, and the horizontal radius is 100m, calculate the angle of inclination of the track to the horizontal and the reaction at the wheels.
tan(theta) = v^2 / rg where r is the radius and g is 10m/s
v = rw, w is the angular speed, r is the radius
F = mrw^2 = mv^2 / r
, F is the force towards the centre of the track, r is the radius, w is the angular speed
Currently in a Junior College, not sure what that equates to in any part of the world but it's sort of a Pre-University education. So that should give you some idea on my knowledge.
I tried drawing a vector diagram as attached. But I can't figure out whether the car is at the extreme of the track so that its horizontal distance is 100m from the track.
However, I'm also unsure if the above equations with radius means horizontal radius. That said, I assumed it to be and I used the above equations to try solving but I couldn't get an answer. Spent over 2 hours and I'm stumped... Anyone care to help? Any help is appreciated!
P.S. the Answer is 42 degrees and 13450N.
Homework Statement
A racing car of 1000kg moves round a banked track at a constant speed of 108km/h. Assuming the total reaction at the wheel is normal to the track, and the horizontal radius is 100m, calculate the angle of inclination of the track to the horizontal and the reaction at the wheels.
Homework Equations
tan(theta) = v^2 / rg where r is the radius and g is 10m/s
v = rw, w is the angular speed, r is the radius
F = mrw^2 = mv^2 / r
, F is the force towards the centre of the track, r is the radius, w is the angular speed
The Attempt at a Solution
Currently in a Junior College, not sure what that equates to in any part of the world but it's sort of a Pre-University education. So that should give you some idea on my knowledge.
I tried drawing a vector diagram as attached. But I can't figure out whether the car is at the extreme of the track so that its horizontal distance is 100m from the track.
However, I'm also unsure if the above equations with radius means horizontal radius. That said, I assumed it to be and I used the above equations to try solving but I couldn't get an answer. Spent over 2 hours and I'm stumped... Anyone care to help? Any help is appreciated!
P.S. the Answer is 42 degrees and 13450N.
Attachments
Last edited: