Gauss' Law - Electric Flux and Electric Field

In summary: The formula for electric flux is q/(permittivity of free space), where q is the enclosed net charge and the permittivity of free space is a constant equal to 8.85 x 10^-12 C^2/(N*m^2).
  • #1
Yuxtapuesto
3
0

Homework Statement



A 2 C charge is spread uniformly in a hollow sphere with a radius of 50 cm.

a) What is the electric flux?

b) What is the magnitude and direction of an electric field 200 cm away?

Homework Equations



Electric flux = q/(permittivity of free space)

E = q/4(pi)(permittivity of free space)r2

q = charge
The permittivity of free space = 8.85 x 10-12 C2/(N*m2)
r = radius

The Attempt at a Solution



Because the electric flux = the enclosed net charge divided by the permittivity of free space (approx. 8.85 x 10-12) I attempted to use this equation. Using 2 C as the net charge, I found the answer to be about 2.26 N*m2/C

I had no idea how to solve the second part of the question, but referenced my book and found this equation:

E = q/4(pi)(permittivity of free space)r2

q = charge
The permittivity of free space = 8.85 x 10-12 C2/(N*m2)
r = radius

My problem with this equation is that it doesn't seem to incorporate both the 50 cm and the 200 cm distances that are given within the question, but using 200 cm as the value of r, I calculated the answer to part b as 8.99 x 109 N/C

Any help would be greatly appreciated!
 
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  • #2
The reason it doesn't incorporate the 50cm i.e. the radius of the sphere is that outside the sphere the electric field is the same as if you concentrated the charge spread throughout the sphere into a point charge at the center of the sphere.

This can be visualised easily by the first equation you gave. The one for the flux. (We are talking about a reference point outside of the sphere) You said that the flux is proportional to the enclosed net charge, hence if it was the flux of a point charge 2C you would get the same result, since the net charge enclosed is the same, as of the sphere.
 
  • #3
Thank you. Can you / anyone possibly verify these answers?
 
  • #4
What do you mean by verifying them? you theory is ok... You just have to substitute thenumerical values...
 
  • #5
I mean that if someone could solve this problem independent of my work and share his or her answer with me, I would greatly appreciate it.
 
  • #6
What is the formula for electric flux
 

1. What is Gauss' Law?

Gauss' Law is a fundamental law in electromagnetism that relates the electric flux through a closed surface to the amount of charge enclosed by that surface.

2. How is Gauss' Law mathematically expressed?

Gauss' Law is expressed as ∫E⋅dA = Qenc0, where ∫E⋅dA is the electric flux through a closed surface, Qenc is the total charge enclosed by that surface, and ε0 is the permittivity of free space.

3. What is electric flux?

Electric flux is a measure of the electric field passing through a given surface. It is a scalar quantity calculated by taking the dot product of the electric field and the surface's area vector.

4. What is the significance of Gauss' Law?

Gauss' Law is significant because it allows us to determine the electric field at any point in space by only considering the charge enclosed within a closed surface surrounding that point. This simplifies calculations and allows for a better understanding of the behavior of electric fields.

5. Can Gauss' Law be applied to any closed surface?

Yes, Gauss' Law can be applied to any closed surface, regardless of its shape or orientation. This is because the electric flux through a closed surface is independent of its shape and only depends on the amount of charge enclosed within it.

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