- #1
WesleyPipes
- 10
- 0
Well, I am raging over my homework and not even going to turn it in because I can't complete enough of it. I really just need to figure this problem out so I don't feel as bad about it. I know this shouldn't be as hard as I am making it, but all examples only have answers containing a single-direction vector.
A line of charge with uniform density Pl=8(uC/m) exists in air along the z-axis between z=0 and z=5 cm. Find E at (0,10cm,0).
R = y(.1)-z(z) --- really Vector(R) = Yhat(.1)-Zhat(z)
Mag(R) = sqrt(.01+z^2)
Rhat' = Vector(R)/Mag(R)
Line Distribution:
E=(1/(4*Pi*Epsilon))*Integral(z=0 to z=0.05)[Rhat'*(Pl)/Mag(R)^2]dL
Sorry if the equations are ridiculously hard to read.
Each time I try this, I get an answer in the +y direction when I feel like the answer vector should be in the (-z,+y) direction.
Thanks guys.
Homework Statement
A line of charge with uniform density Pl=8(uC/m) exists in air along the z-axis between z=0 and z=5 cm. Find E at (0,10cm,0).
Homework Equations
R = y(.1)-z(z) --- really Vector(R) = Yhat(.1)-Zhat(z)
Mag(R) = sqrt(.01+z^2)
Rhat' = Vector(R)/Mag(R)
Line Distribution:
E=(1/(4*Pi*Epsilon))*Integral(z=0 to z=0.05)[Rhat'*(Pl)/Mag(R)^2]dL
The Attempt at a Solution
Sorry if the equations are ridiculously hard to read.
Each time I try this, I get an answer in the +y direction when I feel like the answer vector should be in the (-z,+y) direction.
Thanks guys.