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Black Hole - Conservation of energy? |
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| Jan22-13, 04:57 PM | #1 |
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Black Hole - Conservation of energy?
since energy absorbed by a BH is no longer available to the universe, why is that not a violation of the principle of conservation of energy?
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| Jan22-13, 05:35 PM | #2 |
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Conservation of energy means that the amount of energy contained in a closed system is constant. It makes no claim as to whether the energy is "available" or not.
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| Jan22-13, 05:48 PM | #3 |
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Mentor
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In addition, there is no global energy conservation in General Relativity. If you consider the total energy content of "black hole + stuff you throw in" in an appropriate way, it will stay constant (the black hole grows and increases its mass), but you cannot simply use energy conservation everywhere.
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| Jan23-13, 03:38 PM | #4 |
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Recognitions:
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Black Hole - Conservation of energy?
The conservation law applies to the total of mass plus energy. This total includes the dark energy. The dark energy density (according to current theory) is constant as a function of time. Since the universe is expanding, the total energy in the universe is increasing, rather than constant.
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| Jan24-13, 04:17 AM | #5 |
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@mathman you said the total energy in the universe is increasing , how can that be as energy/mass can't just come from "thin air" ? Where is that energy then coming from in a universe that already has some amount of energy let's say "X"
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| Jan24-13, 09:29 AM | #6 |
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| Jan24-13, 12:59 PM | #7 |
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There is no conservation law for a scalar mass-energy in GR that applies globally in all spacetimes. However, there are measures of mass such as the Komar mass that apply in special cases. The Komar mass is defined and conserved in asymptotically flat spacetimes. If you have a black hole in an asymptotically flat spacetime and drop some mass into it, the total Komar mass is conserved. As PeterDonis pointed out, conservation of mass-energy doesn't have anything to do with whether the mass-energy is "available."
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| Jan24-13, 01:20 PM | #8 |
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| Jan24-13, 03:57 PM | #9 |
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Recognitions:
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| Jan24-13, 08:30 PM | #10 |
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| Jan25-13, 04:47 PM | #11 |
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How about: A static observer hovering outside the horizon supposedly sees a huge amount of energy from the BH horizon...and according to descriptions I have seen gets fried.... What I am unsure about is that apparently the space-times in our models are static...like Schwarzschild..... but when actual matter or a detection device with mass hovers space-time actually becomes dynamic..... The horizon moves outward... It is not clear to me how the static space-time[ idealized model] may affect the above description. In other words, strictly, speaking the models only apply to a "test object observer' hovering for all time...... |
| Jan25-13, 06:53 PM | #12 |
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Recognitions:
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As far as I know, the observer outside the event horizon doesn't see any energy, clasically. And non-clasically he just sees Unruh radiation, which he would see if he were accelerating at the same rate as he needed to be accelerating in flat space-time.
I might have gotten the later part slightly wrong, I'm not as familar with the QM aspects as I wish I was - but i think it's close. There is a place where observers are expected to be fried when falling into relaitic rotating or charged black holes, but that's due to the effect called "mass inflation" and it occurs inside the event horizon. http://casa.colorado.edu/~ajsh/bhtalk_07/inflation.html has a short note, the same author has some more detailed papers. |
| Jan25-13, 07:27 PM | #13 |
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If we try to look at this "semi-classically", I think what this is saying is that when quantum fields are present, there is no such thing as a true "vacuum" stress-energy tensor; i.e., the SET of a quantum field cannot be identically zero. Components of it can vanish in particular frames, but it can't vanish as a whole. |
| Jan25-13, 07:30 PM | #14 |
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http://arxiv.org/abs/1211.6767 |
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