- #1
talaroue
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Homework Statement
A 1209 kg safe is 1.54 m above a heavy-duty spring when the rope holding the safe breaks. Thr safe hits the spring and compress it 53 cm. What is he spring constant of the spring?
Homework Equations
K=mV^2/2
U=mgh
Ki+Ui=Kf+Uf
The Attempt at a Solution
I thought I understood momentuem and energy but not anymore. Here is what I did...
Ui=mgh= 2*9.8*1.54
Kf=mV^2/2
Then solved for V and got 5.494 m/s
Then used that velocity for the spring constant by using...
U=k(delta x)^2/2
K=mV^2/2
then solved for k and got 129912 N/m... but that is coming up wrong what am i doing wrong.