Calculate Asteroid Escape and Final Speeds - Get Help Today!"

  • Thread starter mshah3
  • Start date
In summary, the escape speed from a very small asteroid is 32 m/s and if you throw a rock away from the asteroid at a speed of 37 m/s, its final speed will be 37 m/s. To ensure that the rock never comes back to the asteroid and reaches a speed of 8 m/s when it is very far away, you need to throw it at a speed faster than the escape speed in the direction of the asteroid's spin. The equation to calculate the escape speed is Ve = sqrt((2GM/r)), but the exact setup for incorporating the final and initial velocities into the equation is not known.
  • #1
mshah3
38
0
1. The escape speed from a very small asteroid is only 32 m/s. If you throw a rock away from the asteroid at a speed of 37 m/s, what will be its final speed?

2. How fast (relative to you) do you have to throw the rock (in the direction of the asteroid's spin) so that it never comes back to the asteroid and ends up traveling at a speed of 8 m/s when it is very far away? (I have mass, radius, and escape speed; I just need to know how to set it up)

THANKS
 
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  • #2
I the future post homework help requests in the homework help forums.


Now, Show us that you have tried.
 
  • #3
i know that Ve = sqrt((2GM/r))
but i don't know how to incorporate the final and initial velocities into the equation
 
  • #4
i apologize for placing it in the wrong forum

i'm new to the site
 

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