- #1
Wellesley
- 274
- 3
I believe my question is better suited in this area, instead of Homework, but I may be wrong.
This is what I'm given:
(9x[tex]^{2}[/tex]+y-1) dx - (4y-x) dy =0 y(1) =3
Solve the initial value problem and determine at least where the solution is valid.
I did solve the problem, but I end up with this:
A.) 3x[tex]^{3}[/tex]+xy-x-2y[tex]^{2}[/tex]=2
When my calculator solves for Y, I get the same answer as the book does. However, I'm rather stumped at how the book gets this answer:
B.) y = [x - (24x^3+x^2-8x-16)[tex]^{1/2}[/tex]] / 4.
Can anyone help me to get from point A to point B? Thanks.
This is what I'm given:
(9x[tex]^{2}[/tex]+y-1) dx - (4y-x) dy =0 y(1) =3
Solve the initial value problem and determine at least where the solution is valid.
I did solve the problem, but I end up with this:
A.) 3x[tex]^{3}[/tex]+xy-x-2y[tex]^{2}[/tex]=2
When my calculator solves for Y, I get the same answer as the book does. However, I'm rather stumped at how the book gets this answer:
B.) y = [x - (24x^3+x^2-8x-16)[tex]^{1/2}[/tex]] / 4.
Can anyone help me to get from point A to point B? Thanks.